如何从 wsdl webservice 的 xml 输出中获取 id

Question

我有一个从 java 项目生成的 web 服务 (wsdl)。它的输出是 xml 格式。像这样的

<?xml version="1.0" encoding="UTF-8"?><list><map><entry key="aid">160608</entry><entry key="aDate">2013-10-24 00:00:00.0 IST</entry><entry key="insuranceType">Self Pay</entry><entry key="status">New</entry><entry key="pid">160576</entry><entry key="pChartno" /><entry key="lName">Mathur</entry><entry key="fName">Gaurav</entry><entry key="mName">mathur</entry><entry key="gender">Male</entry><entry key="ssn" /><entry key="providerId">2030</entry><entry key="providerFname">lakshman</entry></map></list>

在我的 cs 文件中，我解析 xml 并将结果放入数据集中。 这是我的代码

DataSet dsresult = new DataSet();
XmlDocument xml = new XmlDocument();
xml.LoadXml("--XML String From Webservice Here--");
XmlElement exelement = xml.DocumentElement;

XmlNodeReader nodereader = new XmlNodeReader(exelement);
dsresult.ReadXml(nodereader, XmlReadMode.Auto);
return dsresult;

现在我将数据集绑定到一个gridview，它只显示这个

Image of grid view here

如何从每个节点（即<entry key="aid">）获取密钥并将“aid”和其他密钥显示为表头？ cs 代码会很有帮助。

我想要一个网格数据，例如 this (Click here for grid image)

编辑 1

对于单行数据，Sam 的代码正在运行。但是当我输入这样的 xml 字符串时

<?xml version="1.0" encoding="UTF-8"?><list><map><entry key="aid">173661</entry><entry key="aDate">2013-10-28 00:00:00.0 IST</entry><entry key="insuranceType">Self Pay</entry><entry key="status">Serviced</entry><entry key="pid">163686</entry><entry key="pChartno" /><entry key="lName">Bec&&kwith</entry><entry key="fName">Burt</entry><entry key="mName" /><entry key="gender">Male</entry><entry key="ssn" /><entry key="providerId">137935</entry><entry key="providerFname">test</entry></map><map><entry key="aid">173675</entry><entry key="aDate">2013-10-28 00:00:00.0 IST</entry><entry key="insuranceType">Self Pay</entry><entry key="status">New</entry><entry key="pid">2038</entry><entry key="pChartno" /><entry key="lName">Velusamy </entry><entry key="fName">Anand</entry><entry key="mName">M</entry><entry key="gender">Male</entry><entry key="ssn">12345690</entry><entry key="providerId">137935</entry><entry key="providerFname">test</entry></map><map><entry key="aid">173679</entry><entry key="aDate">2013-10-28 00:00:00.0 IST</entry><entry key="insuranceType">Self Pay</entry><entry key="status">Serviced</entry><entry key="pid">140417</entry><entry key="pChartno" /><entry key="lName">alex</entry><entry key="fName">pandian</entry><entry key="mName" /><entry key="gender">Male</entry><entry key="ssn" /><entry key="providerId">137935</entry><entry key="providerFname">test</entry></map></list>

它显示这个错误：-“有多个根元素”

Answer 1

试试这个

你的 Xml

<?xml version="1.0" encoding="UTF-8" ?> 
<list>
<map>
 <entry key="aid">160608</entry> 
 <entry key="aDate">2013-10-24 00:00:00.0 IST</entry> 
 <entry key="insuranceType">Self Pay</entry> 
 <entry key="status">New</entry> 
<entry key="pid">160576</entry> 
<entry key="pChartno" /> 
<entry key="lName">Mathur</entry> 
<entry key="fName">Gaurav</entry> 
<entry key="mName">mathur</entry> 
<entry key="gender">Male</entry> 
<entry key="ssn" /> 
<entry key="providerId">2030</entry> 
<entry key="providerFname">lakshman</entry> 
</map>
</list>

private void LoadData()
    {
        XDocument xDoc = XDocument.Load("E:\\test.xml");
        XElement xEle = xDoc.XPathSelectElement("//map");
        List<string> lstValues = new  List<string>();
        if (xEle != null)
        {
            foreach (XElement xElement in xEle.Descendants())
            {
                if (xElement.Attribute("key") != null)
                {
                    lstValues.Add(xElement.Attribute("key").Value); // In this List you will get everything
                }
            }
        }
    }

Answer 2

我尝试了您的 XML，我得到了这个结果。

您需要创建StringReader 的新实例并将您的XML 传递给它。当您 DataSet 将包含 key 和 desc 列时，您需要创建一个 DataTable 以将行转换为列，因此需要额外的功能。

 protected void Page_Load(object sender, EventArgs e)
        {
            DataSet dsresult = new DataSet();
            XmlDocument xml = new XmlDocument();
            xml.LoadXml("<?xml version=\"1.0\" encoding=\"UTF-8\"?><list><map><entry key=\"aid\">160608</entry><entry key=\"aDate\">2013-10-24 00:00:00.0 IST</entry><entry key=\"insuranceType\">Self Pay</entry><entry key=\"status\">New</entry><entry key=\"pid\">160576</entry><entry key=\"pChartno\" /><entry key=\"lName\">Mathur</entry><entry key=\"fName\">Gaurav</entry><entry key=\"mName\">mathur</entry><entry key=\"gender\">Male</entry><entry key=\"ssn\" /><entry key=\"providerId\">2030</entry><entry key=\"providerFname\">lakshman</entry></map></list>");
            XmlElement exelement = xml.DocumentElement;

            dsresult.ReadXml(new XmlTextReader(new System.IO.StringReader(exelement.InnerXml)));

            DataTable transposedTable = GenerateTransposedTable(dsresult.Tables[0]);

            grd.DataSource = transposedTable;
            grd.DataBind();
        }

 private DataTable GenerateTransposedTable(DataTable inputTable)
        {
            DataTable outputTable = new DataTable();

            // Add columns by looping rows

            // Header row's first column is same as in inputTable
            outputTable.Columns.Add(inputTable.Columns[0].ColumnName.ToString());

            // Header row's second column onwards, 'inputTable's first column taken
            foreach (DataRow inRow in inputTable.Rows)
            {
                string newColName = inRow[0].ToString();
                outputTable.Columns.Add(newColName);
            }

            // Add rows by looping columns        
            for (int rCount = 1; rCount <= inputTable.Columns.Count - 1; rCount++)
            {
                DataRow newRow = outputTable.NewRow();

                // First column is inputTable's Header row's second column
                newRow[0] = inputTable.Columns[rCount].ColumnName.ToString();
                for (int cCount = 0; cCount <= inputTable.Rows.Count - 1; cCount++)
                {
                    string colValue = inputTable.Rows[cCount][rCount].ToString();
                    newRow[cCount + 1] = colValue;
                }
                outputTable.Rows.Add(newRow);
            }

            return outputTable;
        }