如果任何孩子通过条件，SQL 将获取所有父/子加入的行

Question

如果任何特定子节点符合一组标准，我想选择一个父节点及其所有子节点。这可以通过单个查询实现吗？

使用两个查询，它看起来像这样：

SELECT p_id INTO target 
FROM parent, children 
WHERE parent.p_id = children.p_id and children.data1 = 'blah';

SELECT * 
FROM parent 
JOIN children ON parent.p_id = children.p_id and children.p_id = target; 
      

.

p_id    name
1       Perice
2       Siward
3       Scottie

c_id    p_id    name
1          1    Arda
2          1    Katrinka
3          2    Gladi
4          3    Hedi
5          3    Didi
6          3    Lorry

如果谓词是 Lorry 的子名称匹配，则结果集将包含

p_id c_id p_name    c_name
3    4    Scottie   Hedi
3    5    Scottie   Didi
3    6    Scottie   Lorry

Answer 1

SELECT parent.*, children.*
FROM parent
INNER JOIN children ON parent.p_id = children.p_id and children.data1 = 'blah';

评论后编辑：

SELECT parent*
FROM parent
WHERE parent.p_id IN (selet children.p_id 
                       FROM childeren 
                       WHERE children.p_id=parent.p_id and chidren.data1='blah')