c#值没有被存储到访问器中

Question

我有 4 个类文件 Driver 类（包含 main 方法） UserInput 类（包含 GenerateLines 和 TxtLoadFile 方法） FileHandling.class（包含 LoadFile 和 LoadingFile 方法） 加密类（目前为空类）

我的问题是我试图让用户选择三个目录中的哪个目录来选择文件。一旦选择，我希望他们输入文件名（.txt），完成后我希望将该值存储并带到 FileHandling 类，并且 LoadFile 访问器将该值存储到“TxtFile”变量中。然后我想在 LoadingFile 方法中使用“TxtFile”来加载文件。 问题是值被存储在 UserInput 类中，但是当我调用：Driver 类中的 LoadingFile 方法时，它会丢弃该值。

请记住，我是仍在学习 C# 的学生，所以可能不是最好的构建程序，因为我只是在练习作业。

编辑：我忘了提到我确实通过调试器检查了这个，但我不知道如何修复它

驱动类：

namespace UniAssignVigereneCipher
{
    class Driver
    {
        static void Main(string[] args)
        {
            UserInput UI = new UserInput();
            Crypting CR = new Crypting();
            FileHandling FH = new FileHandling();

            Console.WriteLine(UI.test);
            Console.WriteLine(UI.test2);
            FH.LoadingFile();

        }
    }
}

用户输入类：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;

namespace UniAssignVigereneCipher
{
    class UserInput
    {
        public string test = GenerateLines();
        public string test2 = TxtLoadFile();

        public static string GenerateLines()
        {
            string input;
            Console.WriteLine("Would you like to encrypt/decrypt a .txt(t) file  or a piece text string(s)?\r\nPlease type (t) or (s)");
            input = Console.ReadLine();

            switch (input)
            {
                case "t":
                case "T":
                    Console.WriteLine("You have selected a txt file.");
                    break;
                case "s":
                case "S":
                    Console.WriteLine("You have selected to input your own text string.");
                    break;
                default:
                    break;
            }

            return input;

        }
        public static string TxtLoadFile()
        {
            FileHandling Location = new FileHandling();
            int n;
            string FileInput;
            string TxtFileLoc;
            Console.WriteLine("Please choose the location of the .txt file you would like to load from.\r\n1 (Current Location): {0} \r\n2 (Desktop): {1} \r\n3 (My Documents): {2}",  Location.CurrentDir, Location.DesktopPath,Location.DocumentsPath);
            FileInput = Console.ReadLine();
            bool test = int.TryParse(FileInput, out n);

            switch (n)
            {
                case 1:
                    Console.WriteLine("File Location: {0} \r\nName of file to load: ", Location.CurrentDir);
                    TxtFileLoc = Console.ReadLine();
                    Location.LoadFile = Location.DesktopPath + "\\" + TxtFileLoc;
                    break;
                case 2:
                    Console.WriteLine("File Location: {0} \r\nName of file to load: ", Location.DesktopPath);
                    TxtFileLoc = Console.ReadLine();
                    Location.LoadFile = Location.DesktopPath + "\\" + TxtFileLoc;
                    break;
                case 3:
                    Console.WriteLine("File Location: {0} \r\nPName of file to load: ", Location.DocumentsPath);
                    TxtFileLoc = Console.ReadLine();
                    Location.LoadFile = Location.DocumentsPath + "\\" + TxtFileLoc;
                    break;
                default:
                    break;
            }         
            return FileInput;
        }
    }
}

文件处理类

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;

namespace UniAssignVigereneCipher
{
    class FileHandling
    {
        public string DesktopPath = Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory);
        public string DocumentsPath = Environment.GetFolderPath(Environment.SpecialFolder.MyDocuments);
        public string CurrentDir = Environment.CurrentDirectory;



        string TxtFile;

        public string LoadFile
        {
            get
            {
                return TxtFile;
            }
            set
            {
                TxtFile = value;
            }
        }

        public void LoadingFile()
        {
            Console.WriteLine("name:" + TxtFile);
            StreamReader LF = new StreamReader(TxtFile);
            string FileContent = LF.ReadLine();
            Console.WriteLine(FileContent);
        }
    }
}

Answer 1

试试：

    static void Main(string[] args)
    {
        UserInput UI = new UserInput();
        Crypting CR = new Crypting();
        FileHandling FH = new FileHandling();

        Console.WriteLine(UI.test);
        Console.WriteLine(UI.test2);
        FH.LoadFile = UI.test2;
        FH.LoadingFile();
    }

注意：将工作方法放入类构造中是很奇怪的。像这样称呼他们可能会更好：

        UserInput UI = new UserInput();
        string textFile = UI.TxtLoadFile();
        //... later on...
        FH.LoadFile = textFile;