在来自 2 个不同的其他字典的键之间拆分字典

Question

我有 3 部字典：

dict1 = {'Name1':'Andrew','Name2':'Kevin'....'NameN':'NameN'}- this would have maximum 20 names
dict2 = {'Travel':'Andrew','Footbal':'Kevin',...'Nhobby':'NameN'}- this would have as many names as there are in dict1
dict3 = {'Travel':'ID01','Footbal':'ID02','Travel':'ID03','Photo':'ID04','Footbal':'ID05','Photo':'ID06','Climbing':'ID07'....}

我想合并这 3 个字典，以便第 3 个以这种方式结束：

 dict3 = {'Andrew':'ID01','Kevin':'ID02','Andrew':'ID03','Kevin':'ID04','Kevin':'ID05','Kevin':'ID06','Andrew':'ID07',....}. Basically the hobbies that are in the dict 2 will be kept while the remaining hobbies will be split among the total number of names with a +1 in the case of an uneven number of hobbies.

我已经从这里Merge dictionaries retaining values for duplicate keys 尝试了合并功能，但我很难将 dict3 平均分配给所有名称。

Answer 1

只有当 dict2 的值是唯一的（因为它们将成为结果字典的键）时，您想要的输出才有可能。在这种情况下，您可以使用：

res_dict = {val: dict3[dict2.keys()[dict2.values().index(val)]] for val in dict1.values()}

输出：

>>> dict1 = {'Name1': 'Andrew', 'Name2': 'Kevin'}
>>> dict2 = {'Travel': 'Andrew', 'Footbal': 'Kevin'}
>>> dict3 = {'Travel': 'ID01', 'Footbal': 'ID02'}

>>> res_dict = {val: dict3[dict2.keys()[dict2.values().index(val)]] for val in dict1.values()}
>>> res_dict
{'Andrew': 'ID01', 'Kevin': 'ID02'}

如果您的 dict2 的值不是唯一的，您可以使用列表来存储 res_dict 值，如下所示：

dict1 = {'Name1': 'Andrew', 'Name2': 'Kevin'}
dict2 = {'Travel': 'Andrew', 'Footbal': 'Kevin', 'Photo': 'Andrew'}
dict3 = {'Travel': 'ID01', 'Footbal': 'ID02', 'Photo': 'ID03'}

res_dict = {}

for val in dict1.values():
    val_keys = []
    for key in dict2.keys():
        if dict2[key] == val:
            val_keys.append(key)
    for item in val_keys:
        if dict2[item] in res_dict:
            res_dict[dict2[item]].append(dict3[item])
        else:
            res_dict[dict2[item]] = [dict3[item]]

输出：

>>> res_dict
{'Andrew': ['ID03', 'ID01'], 'Kevin': ['ID02']}