在使用 python 从字典列表中提取值计数时需要帮助

Question

我希望使用 Python 计算字典列表中的键值的百分比及其对应的计数以及值及其对应的计数。

使用下面的代码来提取键及其计数。需要帮助来扩展它以提取值及其相应的计数。

数据如下所示：

people = [
    {"name": "Tom", "age": 10, "city": "NewYork"},
    {"name": "Mark", "age": 5, "country": "Japan"},
    {"name": "Pam", "age": 7, "city": "London"},
    {"name": "Tom", "hight": 163, "city": "California"},
    {"name": "Lena", "weight": 45, "country": "Italy"},
    {"name": "Ben", "age": 17, "city": "Colombo"},
    {"name": "Lena", "gender": "Female", "country": "Italy"},
    {"name": "Ben", "gender": "Male", "city": "Colombo"},
]


def getKeyCount(lst):
    out = {}
    for d in lst:
        for k in d.keys():
            out[k] = out.get(k, 0) + 1
    return out


def getValCount(lst):
    out = {}
    for d in lst:
        for v in d.values():
            out[v] = out.get(v, 0) + 1
    return out


getKeyCount(people)
# {'name': 8, 'age': 4, 'city': 5, 'country': 3,
# 'hight': 1, 'weight': 1, 'gender': 2}

getValCount(people)
# {'Tom': 2, 'NewYork': 1, 'Mark': 1, 'Japan': 1, 'Pam': 1,
# 'London': 1, 'California': 1, etc.}

我想要这样的输出：

Name: 10
'Tom': 2, 'Mark': 3, 'Pam': 1,'Lena': 3, 'Ben': 2
City:4
'London': 1, 'California': 1, 'NewYork': 2

我是新手，谁能帮帮我？

Answer 1

试试：

from collections import Counter, defaultdict

people = [
    {"name": "Tom", "age": 10, "city": "NewYork"},
    {"name": "Mark", "age": 5, "country": "Japan"},
    {"name": "Pam", "age": 7, "city": "London"},
    {"name": "Tom", "hight": 163, "city": "California"},
    {"name": "Lena", "weight": 45, "country": "Italy"},
    {"name": "Ben", "age": 17, "city": "Colombo"},
    {"name": "Lena", "gender": "Female", "country": "Italy"},
    {"name": "Ben", "gender": "Male", "city": "Colombo"},
]

cnt = defaultdict(Counter)
for p in people:
    if not isinstance(p, dict):  # <-- make sure the items are dicts
        continue

    for k, v in p.items():
        cnt[k].update([v])

for k, v in cnt.items():
    print(k, sum(cnt[k].values()))
    for kk, vv in v.items():
        print("{}: {}".format(kk, vv), end=" ")
    print("\n")

打印：

name 8
Tom: 2 Mark: 1 Pam: 1 Lena: 2 Ben: 2 

age 4
10: 1 5: 1 7: 1 17: 1 

city 5
NewYork: 1 London: 1 California: 1 Colombo: 2 

country 3
Japan: 1 Italy: 2 

hight 1
163: 1 

weight 1
45: 1 

gender 2
Female: 1 Male: 1 

---

更新：添加了检查值的类型为dict

Answer 2

您可以尝试对每个值使用list.count 方法来获取每个值的计数：

people = [{'name': "Tom", 'age': 10, "city" : "NewYork"},
          {'name': "Mark", 'age': 5, "country" : "Japan"},
          {'name': "Pam", 'age': 7, "city" : "London"},
          {'name': "Tom", 'hight': 163, "city" : "California"},
          {'name': "Lena", 'weight': 45, "country" : "Italy"},
          {'name': "Ben", 'age': 17, "city" : "Colombo"},
          {'name': "Lena", 'gender': "Female", "country" : "Italy"},
          {'name': "Ben", 'gender': "Male", "city" : "Colombo"}]

def getKeyCount(lst):
    out = {}
    for d in lst:
        for k in d:
            out[k] = out.get(k, []) + [d[k]]
    return out

d = getKeyCount(people)

def display(d, key):
    vals = d[key]
    print("Name:", len(vals))
    print(', '.join(f"{val}: {vals.count(val)}" for val in set(vals)))

display(d, 'name')
display(d, 'city')

输出：

Name: 8
Mark: 1, Ben: 2, Tom: 2, Pam: 1, Lena: 2
City: 5
London: 1, NewYork: 1, Colombo: 2, California: 1