RDLC - 本地报告处理期间发生错误。报告定义无效

Question

我有一个报告表格“Form1ReportSale”。在它的加载事件上，我想根据来自另一个表单的 ID 生成 RDLC 报告。当我将程序置于调试模式时，DataSet 返回预期值但抛出错误。

请找附件

我的“Form1ReortSale”加载事件代码如下：

public partial class Form1ReportSale : Form
{
    string CS;
    private string id;
    public string UserID
    {
        get { return id; }
        set { id = value; }
    }
    public Form1ReportSale()
    {
        InitializeComponent();
        CS = ConfigurationManager.ConnectionStrings["BikeDB"].ConnectionString;
    }

    private void Form1ReportSale_Load(object sender, EventArgs e)
    {
        this.WindowState = FormWindowState.Maximized;
        //DataSet1NewCustomerBike dsCustomers = GetData(id);
        reportViewer1.ProcessingMode = ProcessingMode.Local;
        reportViewer1.LocalReport.ReportPath = @"E:\Working Area\Directorate Of IT Project\Own Practices\BikeShowRoom\BikeShowRoom\Reports\Form1ReportSale.cs";
        DataSet ds = new DataSet();
        ds = getDataByID(Convert.ToInt32(id));
        ReportDataSource datasource = new ReportDataSource("DataSet1Customer",ds.Tables[0]);
        this.reportViewer1.LocalReport.DataSources.Clear();
        reportViewer1.LocalReport.DataSources.Add(datasource);
        reportViewer1.LocalReport.Refresh();
        reportViewer1.RefreshReport();
    }

    private DataSet getDataByID(int ID)
    {
        DataSet ds = new DataSet();
        using (SqlConnection con = new SqlConnection(CS))
        {
            SqlCommand cmd = new SqlCommand("SELECT * FROM AddNewBike WHERE ID = '"+ID+"'", con);
            SqlDataAdapter ad = new SqlDataAdapter(cmd);
            con.Open();
            ad.Fill(ds);
        }
        return ds;
    }
}

Answer 1

查看您提供的路径：

reportViewer1.LocalReport.ReportPath = @"E:\Working Area\Directorate Of IT Project\Own Practices\BikeShowRoom\BikeShowRoom\Reports\Form1ReportSale.cs";

Form1ReportSale 报告扩展名应该是 .rdlc 而不是 .cs ...复制您为报告提供的正确名称...或试试这个

reportViewer1.LocalReport.ReportPath = "~/Reports/Form1ReportSale.rdlc";