【问题标题】:How to convert pandas Series to desired JSON format?如何将熊猫系列转换为所需的 JSON 格式?
【发布时间】:2016-09-20 16:50:09
【问题描述】:

我有以下数据,我需要对其应用聚合函数,然后是 groupby。

我的数据如下:data.csv

id,category,sub_category,count
0,x,sub1,10
1,x,sub2,20
2,x,sub2,10
3,y,sub3,30
4,y,sub3,5
5,y,sub4,15
6,z,sub5,20

在这里,我试图按子类别进行计数。之后,我需要以 JSON 格式存储结果。以下代码可以帮助我实现这一目标。 test.py

import pandas as pd
df = pd.read_csv('data.csv')
sub_category_total = df['count'].groupby([df['category'], df['sub_category']]).sum()
print sub_category_total.reset_index().to_json(orient = "records")

上面的代码给了我以下格式。

[{"category":"x","sub_category":"sub1","count":10},{"category":"x","sub_category":"sub2","count":30},{"category":"y","sub_category":"sub3","count":35},{"category":"y","sub_category":"sub4","count":15},{"category":"z","sub_category":"sub5","count":20}]

但是,我想要的格式如下:

{
"x":[{
     "sub_category":"sub1",
     "count":10
     },
     {
     "sub_category":"sub2",
      "count":30}],
"y":[{
     "sub_category":"sub3",
     "count":35
     },
     {
     "sub_category":"sub4",
     "count":15}],
"z":[{
     "sub_category":"sub5",
      "count":20}]
}

通过关注@How to convert pandas DataFrame result to user defined json format 的讨论,我将test.py 的最后两行替换为,

g = df.groupby('category')[["sub_category","count"]].apply(lambda x: x.to_dict(orient='records'))
print g.to_json()

它给了我以下输出。

{"x":[{"count":10,"sub_category":"sub1"},{"count":20,"sub_category":"sub2"},{"count":10,"sub_category":"sub2"}],"y":[{"count":30,"sub_category":"sub3"},{"count":5,"sub_category":"sub3"},{"count":15,"sub_category":"sub4"}],"z":[{"count":20,"sub_category":"sub5"}]}

虽然上述结果与我想要的格式有些相似,但我无法在此处执行任何聚合函数,因为它会抛出错误说'numpy.int64' object has no attribute 'to_dict'。因此,我最终得到了数据文件中的所有行。

有人可以帮我实现上述 JSON 格式吗?

【问题讨论】:

    标签: json python-2.7 pandas data-cleaning to-json


    【解决方案1】:

    我觉得你可以先用sum聚合,参数as_index=False加到groupby,所以输出是Dataframedf1再用other solution

    df1 = (df.groupby(['category','sub_category'], as_index=False)['count'].sum())
    print (df1)
      category sub_category  count
    0        x         sub1     10
    1        x         sub2     30
    2        y         sub3     35
    3        y         sub4     15
    4        z         sub5     20
    
    g = df1.groupby('category')[["sub_category","count"]]
           .apply(lambda x: x.to_dict(orient='records'))
    
    print (g.to_json())
    
    {
        "x": [{
            "sub_category": "sub1",
            "count": 10
        }, {
            "sub_category": "sub2",
            "count": 30
        }],
        "y": [{
            "sub_category": "sub3",
            "count": 35
        }, {
            "sub_category": "sub4",
            "count": 15
        }],
        "z": [{
            "sub_category": "sub5",
            "count": 20
        }]
    }
    

    【讨论】:

    • 谢谢。顺便说一句,非常好question。 ;)
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