【问题标题】:Nested json to csv - generic approach将 json 嵌套到 csv - 通用方法
【发布时间】:2016-10-08 22:46:38
【问题描述】:

我对 Python 非常陌生,我正在努力将嵌套的 json 文件转换为 cvs。为此,我首先加载json,然后将其转换为使用json_normalize 打印出漂亮输出的方式,然后使用pandas 包将标准化部分输出到cvs

我的示例 json:

[{
 "_id": {
   "id": "123"
 },
 "device": {
   "browser": "Safari",
   "category": "d",
   "os": "Mac"
 },
 "exID": {
   "$oid": "123"
 },
 "extreme": false,
 "geo": {
   "city": "London",
   "country": "United Kingdom",
   "countryCode": "UK",
   "ip": "00.000.000.0"
 },
 "viewed": {
   "$date": "2011-02-12"
 },
 "attributes": [{
   "name": "gender",
   "numeric": 0,
   "value": 0
 }, {
   "name": "email",
   "value": false
 }],
 "change": [{
   "id": {
     "$id": "1231"
   },
   "seen": [{
     "$date": "2011-02-12"
   }]
 }]
}, {
 "_id": {
   "id": "456"
 },
 "device": {
   "browser": "Chrome 47",
   "category": "d",
   "os": "Windows"
 },
 "exID": {
   "$oid": "345"
 },
 "extreme": false,
 "geo": {
   "city": "Berlin",
   "country": "Germany",
   "countryCode": "DE",
   "ip": "00.000.000.0"
 },
 "viewed": {
   "$date": "2011-05-12"
 },
 "attributes": [{
   "name": "gender",
   "numeric": 1,
   "value": 1
 }, {
   "name": "email",
   "value": true
 }],
 "change": [{
   "id": {
     "$id": "1231"
   },
   "seen": [{
     "$date": "2011-02-12"
   }]
 }]
}]

使用以下代码(这里我排除了嵌套部分):

import json
from pandas.io.json import json_normalize


def loading_file():
    #File path
    file_path = #file path here

    #Loading json file
    json_data = open(file_path)
    data = json.load(json_data)
    return data

#Storing avaliable keys
def data_keys(data):
    keys = {}
    for i in data:
        for k in i.keys():
            keys[k] = 1

    keys = keys.keys()

#Excluding nested arrays from keys - hard coded -> IMPROVE
    new_keys = [x for x in keys if
    x != 'attributes' and
    x != 'change']

    return new_keys

#Excluding nested arrays from json dictionary
def new_data(data, keys):
    new_data = []
    for i in range(0, len(data)):
        x = {k:v for (k,v) in data[i].items() if k in keys }
        new_data.append(x)
    return new_data

 def csv_out(data):
     data.to_csv('out.csv',encoding='utf-8')

def main():
     data_file = loading_file()
     keys = data_keys(data_file)
     table = new_data(data_file, keys)
     csv_out(json_normalize(table))

main()

我当前的输出如下所示:

| _id.id | device.browser | device.category | device.os |  ... | viewed.$date |
|--------|----------------|-----------------|-----------|------|--------------|
| 123    | Safari         | d               | Mac       | ...  | 2011-02-12   |
| 456    | Chrome 47      | d               | Windows   | ...  | 2011-05-12   |
|        |                |                 |           |      |              |

我的问题是我想将嵌套数组包含到 cvs 中,所以我必须将它们展平。我不知道如何使它通用,所以我在创建表时不使用字典 keys (numeric, id, name) 和 values。我必须使其具有普遍性,因为attributeschange 中的键数。因此,我希望有这样的输出:

| _id.id | device.browser | ... | attributes_gender_numeric | attributes_gender_value | attributes_email_value | change_id | change_seen |
|--------|----------------|-----|---------------------------|-------------------------|------------------------|-----------|-------------|
| 123    | Safari         | ... | 0                         | 0                       | false                  | 1231      | 2011-02-12  |
| 456    | Chrome 47      | ... | 1                         | 1                       | true                   | 1231      | 2011-02-12  |
|        |                |     |                           |                         |                        |           |             |

提前感谢您!非常欢迎任何关于如何改进我的代码并使其更高效的提示。

【问题讨论】:

    标签: python json csv pandas


    【解决方案1】:

    感谢 Amir Ziai 的精彩博文,您可以找到 here 我设法以平面表格的形式输出我的数据。具有以下功能:

    #Function that recursively extracts values out of the object into a flattened dictionary
    def flatten_json(data):
        flat = [] #list of flat dictionaries
        def flatten(y):
            out = {}
    
            def flatten2(x, name=''):
                if type(x) is dict:
                    for a in x:
                        if a == "name": 
                                flatten2(x["value"], name + x[a] + '_')
                        else:  
                            flatten2(x[a], name + a + '_')
                elif type(x) is list:
                    for a in x:
                        flatten2(a, name + '_')
                else:
                    out[name[:-1]] = x
    
            flatten2(y)
            return out
    
    #Loop needed to flatten multiple objects
        for i in range(len(data)):
            flat.append(flatten(data[i]).copy())
    
        return json_normalize(flat) 
    

    我知道由于名称-值 if 语句,它不是完全可推广的。但是,如果删除了创建名称-值字典的豁免,则该代码可以与其他嵌入式数组一起使用。

    【讨论】:

      【解决方案2】:

      几周前,我有一项任务是将带有嵌套键和值的 json 转换为 csv 文件。对于此任务,必须正确处理嵌套键以连接要用作值的唯一标头。结果是下面的代码,也可以找到here

      def get_flat_json(json_data, header_string, header, row):
          """Parse json files with nested key-vales into flat lists using nested column labeling"""
          for root_key, root_value in json_data.items():
              if isinstance(root_value, dict):
                  get_flat_json(root_value, header_string + '_' + str(root_key), header, row)
              elif isinstance(root_value, list):
                  for value_index in range(len(root_value)):
                      for nested_key, nested_value in root_value[value_index].items():
                          header[0].append((header_string +
                                            '_' + str(root_key) +
                                            '_' + str(nested_key) +
                                            '_' + str(value_index)).strip('_'))
                          if nested_value is None:
                              nested_value = ''
                          row[0].append(str(nested_value))
              else:
                  if root_value is None:
                      root_value = ''
                  header[0].append((header_string + '_' + str(root_key)).strip('_'))
                  row[0].append(root_value)
          return header, row
      

      这是一种基于经济学家对此问题的回答的更通用的方法。

      【讨论】:

        【解决方案3】:

        以下代码处理了一个杂乱无章的 json 文件 字典和列表相互之间 7 层深:

            import csv, json, os
            def parse_json(data):
                a_dict_accum = {}
                for key, val in data.items():
                    print("key, val = ", key, val)
                    output.writerow([key])
                    output.writerow([val])
                    if isinstance(val, dict):
                        for a_key, a_val in val.items():
                            print("a_key, a_val = ", a_key, a_val)
                            output.writerow([a_key])
                            output.writerow([a_val])
                            a_dict_accum.update({a_key:a_val})
                        print("a_dict_accum = ", a_dict_accum)
                        parse_json(a_dict_accum)
                    elif isinstance(val, list):
                        print("val_list = ", val)
                        for a_list in val:
                             print("a_list = ", a_list)
                             output.writerow([a_list])
                             if isinstance(a_list, dict):
                                 for a_key, a_val in a_list.items():
                                     print("a_key, a_val = ", a_key, a_val)
                                     output.writerow([a_key])
                                     output.writerow([a_val])    
                                     a_dict_accum.update({a_key:a_val})
                                 print("a_dict_accum = ", a_dict_accum)
                                 parse_json(a_dict_accum)
            os.chdir('C://Users/Robert/viirs/20200217_output')
            fileInput = 'night_lights_points.json'
            fileOutput = 'night_lights_points.csv'
            inputFile = open(fileInput) #open json file
            outputFile = open(fileOutput, 'w', newline='') #load csv file
            data = json.load(inputFile) #load json content
            output = csv.writer(outputFile) #create a csv.writer
            output = parse_json(data)
            inputFile.close() #close the input file
            outputFile.close() #close the output file       
                        
                    
        

        【讨论】:

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