xml 显式类型属性

Question

我尝试结束我的 SQL 以获得提要输出...但我又遇到了一个复杂问题。首先，我要感谢我不是用于 XML 输出的 SQL 专家……但希望得到某人的帮助。

使用这个查询

SELECT 
    1487997 as ExternalId,
    'This is a name' as [Name]
INTO #sample

DROP TABLE #colors
SELECT 
    1487997 as ExternalId,
    'BV_FE_FAMILY:Green' as [Color]
INTO #colors
UNION 
SELECT
    1487997 as ExternalId,
    'Green' as [Color]

SELECT
    1 as Tag,
    NULL as Parent,
    NULL AS [EliminaTAG!1], -- empty root element
    NULL AS [Product!2!ExternalId!element],
    NULL AS [Product!2!Name!cdata],
    NULL AS [Product!2!]
UNION ALL
SELECT 
    2 AS Tag,
    1 AS Parent,
    NULL,
    ExternalId,  
    [Name],
    (
     SELECT  
       c.[Color] as Value
     FROM #colors  c 
     WHERE (ff.ExternalId = c.ExternalId)   
     FOR XML PATH('Attribute'), ROOT('Attributes'), TYPE)
FROM #sample ff 
FOR XML EXPLICIT

我已经接近我的范围...但我需要一个 id="BV_FE_FAMILY" 和 id="BV_FE_EXPAND" 进入 TAG...

<Attributes>
<Attribute id="BV_FE_FAMILY">
    <Value>Green</Value>
<Attribute>
<Attribute id="BV_FE_EXPAND">
    <Value>BV_FE_FAMILY:Green</Value>
<Attribute>
</Attributes>

我的结果是……错过“ID=.....”

    <EliminaTAG>
      <Product>
        <ExternalId>1487997</ExternalId>
        <Name><![CDATA[This is a name]]></Name>
        <Attributes xmlns="">
          <Attribute>
              <Value>Green</Value>
          </Attribute>
          <Attribute>
              <Value>BV_FE_FAMILY:Green</Value>
          </Attribute>
        </Attributes>
      </Product>
   </EliminaTAG>

感谢所有能给我正确建议的人。 意大利阿伦

Answer 1

正如我在评论中指出的那样，FOR XML EXPLICIT 是一个相当笨拙的选择。但是有一些要求，否则无法解决...

所以，如果你真的需要这个，你可能会更容易解决：

SELECT
    1 as Tag,
    NULL as Parent,
    ff.ExternalId AS [Product!1!ExternalId!element],
    ff.Name AS [Product!1!Name!cdata],
    (
     SELECT  'SomeValueForId' AS [@id]
            ,c.Color AS [Value]
     FROM #colors c
     WHERE c.ExternalId=ff.ExternalId
     FOR XML PATH('Attribute'),ROOT('Attributes'),TYPE
    ) AS [Product!1!]
FROM #sample ff 
FOR XML EXPLICIT,ROOT('EliminaTAG');

结果

<EliminaTAG>
  <Product>
    <ExternalId>1487997</ExternalId>
    <Name><![CDATA[This is a name]]></Name>
    <Attributes xmlns="">
      <Attribute id="SomeValueForId">
        <Value>BV_FE_FAMILY:Green</Value>
      </Attribute>
      <Attribute id="SomeValueForId">
        <Value>Green</Value>
      </Attribute>
    </Attributes>
  </Product>
</EliminaTAG>

我不明白你的id 属性的内容来自哪里，这取决于你。

Answer 2

非常感谢您的帮助和建议... 我用你的代码解决了他的问题：

SELECT
    1 as Tag,
    NULL as Parent,
    ff.ExternalId AS [Product!1!ExternalId!element],
    ff.Name AS [Product!1!Name!cdata],
    (
     SELECT  
            CASE
                WHEN CHARINDEX('BV_FE_FAMILY', c.Color) > 0 THEN 'BV_FE_EXPAND' 
                ELSE 'BV_FE_FAMILY'
            END AS [@id]
            ,c.Color AS [Value]
     FROM #colors c
     WHERE c.ExternalId=ff.ExternalId
     FOR XML PATH('Attribute'),ROOT('Attributes'),TYPE
    ) AS [Product!1!]
FROM #sample ff 
FOR XML EXPLICIT;

这是我输出的结果

<Product>
  <ExternalId>1487997</ExternalId>
  <Name><![CDATA[This is a name]]></Name>
  <Attributes xmlns="">
    <Attribute id="BV_FE_EXPAND">
      <Value>BV_FE_FAMILY:Green</Value>
    </Attribute>
    <Attribute id="BV_FE_FAMILY">
      <Value>Green</Value>
    </Attribute>
  </Attributes>
</Product>

可以删除这个 xmlns="" 吗？ 目前，我将在 ETL 过程中将其删除，以便直接将 XML 文件创建到 SSIS 中......但如果有直接来自 T-SQL 的干净方式，我更喜欢...... 无论如何谢谢Shnugo！ 阿伦

P.S.：这是另一个使用（如您所说）FROM XML PATH 的版本，但是如何为某些元素插入 cdata？此选择已删除 xmlns=""...

SELECT
    ff.ExternalId ,
    ff.Name,
    (
     SELECT  
            CASE
                WHEN CHARINDEX('BV_FE_FAMILY', c.Color) > 0 THEN 'BV_FE_EXPAND' 
                ELSE 'BV_FE_FAMILY'
            END AS [@id]
            ,c.Color AS [Value]
     FROM #colors c
     WHERE c.ExternalId=ff.ExternalId
     FOR XML PATH('Attribute'),ROOT('Attributes'),TYPE
    ) 
FROM #sample ff 
FOR XML PATH('Product'), ROOT('Products');

这是我的最终解决方案（CAST + REPLACE + CAST）：

SELECT
    ff.ExternalId ,
    ff.Name,
    CAST(REPLACE(CAST((
     SELECT  
            CASE
                WHEN CHARINDEX('BV_FE_FAMILY', c.Color) > 0 THEN 'BV_FE_EXPAND' 
                ELSE 'BV_FE_FAMILY'
            END AS [@id]
            ,c.Color AS [Value]
     FROM #colors c
     WHERE c.ExternalId=ff.ExternalId
     FOR XML PATH('Attribute'),ROOT('Attributes'),TYPE
    )  as varchar(MAX)),' xmlns=""','') as xml)
FROM #sample ff 
FOR XML PATH('Product'), ROOT('Products');

我的干净结果输出：

<Products>
  <Product>
    <ExternalId>1487997</ExternalId>
    <Name>This is a name</Name>
    <Attributes>
      <Attribute id="BV_FE_EXPAND">
        <Value>BV_FE_FAMILY:Green</Value>
      </Attribute>
      <Attribute id="BV_FE_FAMILY">
        <Value>Green</Value>
      </Attribute>
    </Attributes>
  </Product>
</Products>

阿伦

Answer 3

这是最终代码：

SELECT
    ff.ExternalId ,
    ff.Name as Name,
    'http://www.mysite.it/imgege.jpg' as URL,
    CAST(CAST((
     SELECT  
            CASE
                WHEN CHARINDEX('BV_FE_FAMILY', c.Color) > 0 THEN 'BV_FE_EXPAND' 
                ELSE 'BV_FE_FAMILY'
            END AS [@id]
            ,c.Color AS [Value]
     FROM #colors c
     WHERE c.ExternalId=ff.ExternalId
     FOR XML PATH('Attribute'),ROOT('Attributes'),TYPE
    )  as nvarchar(MAX)) as xml)
FROM #sample ff 
FOR XML PATH('Product'), ROOT('Products');

还有我的输出...

<Products>
  <Product>
    <ExternalId>1487997</ExternalId>
    <Name>This is a name</Name>
    <URL>http://www.mysite.it/imgege.jpg</URL>
    <Attributes>
      <Attribute id="BV_FE_EXPAND">
        <Value>BV_FE_FAMILY:Green</Value>
      </Attribute>
      <Attribute id="BV_FE_FAMILY">
        <Value>Green</Value>
      </Attribute>
    </Attributes>
  </Product>
</Products>