【问题标题】:MongoDB Show children items in One to Many relationshipMongoDB以一对多关系显示子项
【发布时间】:2016-09-10 12:21:24
【问题描述】:

这是 1:N 关系的例子。 有一个根项,由几个项(子项)组成:

{
    "_id" : ObjectId("52d017d4b60fb046cdaf4851"),
    "dates" : [
        1399518702000,
        1399126333000,
        1399209192000,
        1399027545000
    ],
    "dress_number" : "4",
    "name" : "J. Evans",
    "numbers" : [
        "5982",
        "5983",
        "5984",
        "5985"
    ],
    "goals": [
        "1",
        "0",
        "4",
        "2"
    ],
   "durations": [
       "78",
       "45",
       "90",
       "90"
   ]
}

我想要做的是显示来自根项目的子数据:

{
    "dates": "1399518702000",
    "numbers": "5982",
    "goals": "1",
    "durations: "78"
},
{
    "dates": "1399126333000",
    "numbers": "5983",
    "goals": "0",
    "durations": "45"
},
{
    "dates": "1399209192000",
    "numbers": "5984",
    "goals": "4",
    "durations": "90"
},
{
    "dates": "1399027545000",
    "numbers": "5985",
    "goals": "2",
    "durations": "90"
}

在表结构中会是这样的:

根项目:

  name      number
J. Evans      4 

儿童用品

 dates           numbers        goals           durations
 1399518702000        5982            1             78
 1399126333000        5983            0             45
 1399209192000        5984            4             90
 1399027545000        5985            2             90

我正在尝试使用$unwind 运算符来执行这种情况:

db.coll.aggregate([{ $unwind: "dates" }, { $unwind: "numbers" }, { $unwind: "goals" }, { $unwind: "durations"} ])

但是查询没有给出预期的数据:/ Here 是很好的解决方案,但只适用于两个数组。

【问题讨论】:

    标签: mongodb mongodb-query aggregation-framework


    【解决方案1】:

    下面的管道应该会给你这个想法

    db.getCollection('yourCollection').aggregate(
        {
            $unwind: {
                path: "$dates",
                includeArrayIndex: "idx"
            }
        },
        {
            $project: {
                _id: 0,
                dates: 1,
                numbers: { $arrayElemAt: ["$numbers", "$idx"] },
                goals: { $arrayElemAt: ["$goals", "$idx"] },
                durations: { $arrayElemAt: ["$durations", "$idx"] }
            }
        }
    )
    

    为您的示例生成以下输出

    /* 1 */
    {
        "dates" : NumberLong(1399518702000),
        "numbers" : "5982",
        "goals" : "1",
        "durations" : "78"
    }
    
    /* 2 */
    {
        "dates" : NumberLong(1399126333000),
        "numbers" : "5983",
        "goals" : "0",
        "durations" : "45"
    }
    
    /* 3 */
    {
        "dates" : NumberLong(1399209192000),
        "numbers" : "5984",
        "goals" : "4",
        "durations" : "90"
    }
    
    /* 4 */
    {
        "dates" : NumberLong(1399027545000),
        "numbers" : "5985",
        "goals" : "2",
        "durations" : "90"
    }
    

    【讨论】:

    • 我有几乎相同的问题,但无法使用相同的查询修复
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