【发布时间】:2021-08-31 02:54:28
【问题描述】:
我有 const 语言数组。我希望所有语言都用作我的模式对象的键。我已经将我的语言数组设置为常量并循环遍历它以获取每种语言的值并将其导出,现在我将其导入到我的架构中并将其用作关键变量,但我遇到了错误
language constant
const languages = [
"Albanian",
"Amharic",
" Arabic ",
" Armenia",
" Azerbaij",
" Basque ",
" Belarusi",
" Bengali ",
" Bosnian ",
" Bulgaria",
" Catalan ",
" Cebuano",
" Chinese",]
export function languageSelector() {
for (let i = 0; i < languages.length - 1; i++) {
return languages[i];
}
}
schema object
import * as mongoose from "mongoose";
import { visibilityPlugin } from "./plugins/visibility";
import { languageSelector } from "./constant";
const ObjectId = mongoose.Schema.Types.ObjectId;
export const TranscriptSchema = mongoose.Schema({
[languageSelector]: [
{
startTime: {
type: String,
},
endTime: {
type: String,
},
text: {
type: String,
},
},
],
confidenceLevel: {
type: Number,
},
videoRef: {
type: ObjectId,
required: true,
ref: "videos",
},
});
【问题讨论】:
-
languageSelector 是一个函数。你想要一个函数作为键吗?
-
@TusharShahi 不,我希望语言作为键,对于每种语言我想在模式中创建相同的 obj
-
那么您将不得不导出语言并导入相同的语言。哪种语言应该是您在集合中的键,还是您希望所有语言都有不同的键?
-
@TusharShahi 我希望所有语言都是关键
-
首先,您的函数将始终返回第一种语言“阿尔巴尼亚语”。它的移动距离不超过 0。