从结构中获取信息并在另一个功能中使用[关闭]

Question

我想知道我是否可以调用结构中的轮胎压力信息并在另一个函数中使用它？基本上我不知道如何从一个到另一个调用它。我必须在轮胎测试中声明函数吗？这是我试图访问轮胎压力信息的功能。感谢您的帮助

#include <stdio.h>
#include <stdlib.h>
#include <time.h>


struct tires
{
    char Manufacturer[40];
    int tire_pressure[0];
    int pressure_change[0];
}typedef tires;
// Prototypes
void getTireInformation(tires*, int);
void tirePressure(tires*, int);
void tireTest(tires*, int);
int main()
{
    tires tire[4];
    tires* ptire = &tire[0];
    srand(time(NULL));

    getTireInformation(ptire, 4);
    tirePressure(ptire, 4);
    tireTest(ptire, 4);

    return 0;
}// end main
//============================
void getTireInformation(tires* ptire, int size)
{
    int i = 0;
    for (i = 0; i < size; i++)
    {
        printf("please enter Make for the tire: \n");
        scanf("%s", &(ptire + i) ->Manufacturer);


    }

    printf("all tire make you entered ...just for verification:\n");
    for(i = 0; i < size; i++)
        printf("%s\n",(ptire +i) ->Manufacturer);

}//end getTireInformation
//=======================================================================

void tirePressure(tires* ptire, int size)
{
    int i = 0;
    int min = 18;
    int max = 35;
    for (i = 0; i < size; i++)
    {
        (ptire + i) ->tire_pressure[0] = rand() % (max - min + 1) + min;
        printf("The Tire pressure is: ");
        printf("%d\n",(ptire + i) -> tire_pressure[0]);
    }// end for
}// end tirePressure
//==============================================================
void tireTest(tires* ptire, int size)
{
    int i = 0;
    int min = 2;
    int max = 5;
    int change[0] = {0};
    i++;
    for (i = 0; i < size; i++)
    {
        change[0] = rand() % (max - min + 1) + min;
        //(ptire + i) -> pressure_change[0] = rand() % (max - min + 1) + min;
        printf("Pressure change from test %d: %d\n",i + 1, change[0]);
        //(ptire + i) -> pressure_change[0] = change[0] + tirePressure;
        //printf("%d\n", (ptire +i) -> pressure_change);
    }// end for

}

Answer 1

我认为你让问题变得比现在更困难——看看这种简化是否能解决你的问题：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define PRESSURE_MIN 18
#define PRESSURE_MAX 35

struct tires
{
    char Manufacturer[40];
    int tire_pressure;
    int pressure_change;
} typedef tires;

// Prototypes
void getTireInformation(tires *, int);
void tirePressure(tires *, int);
void tireTest(tires *, int);

//===============================================================

void getTireInformation(tires *ptire, int size)
{
    for (int i = 0; i < size; i++)
    {
        printf("please enter Make for the tire: \n");
        scanf("%s", ptire[i].Manufacturer);
    }

    printf("all the tire makes you entered ... just for verification:\n");

    for (int i = 0; i < size; i++)
    {
        printf("%s\n", ptire[i].Manufacturer);
    }

} // end getTireInformation

//===============================================================

void tirePressure(tires *ptire, int size)
{
    for (int i = 0; i < size; i++)
    {
        ptire[i].tire_pressure = rand() % (PRESSURE_MAX - PRESSURE_MIN + 1) + PRESSURE_MIN;
        printf("The Tire pressure is: ");
        printf("%d\n", ptire[i].tire_pressure);
    } // end for
} // end tirePressure

//==============================================================

void tireTest(tires *ptire, int size)
{
    int min = 2;
    int max = 5;

    for (int i = 0; i < size; i++)
    {
        int change = rand() % (max - min + 1) + min;

        printf("Pressure change from test %d: %d\n", i + 1, change);

        ptire[i].pressure_change = change + ptire[i].tire_pressure;

        printf("%d\n", ptire[i].pressure_change);
    } // end for
}

//===============================================================

int main()
{
    tires tire[4];

    srand(time(NULL));

    getTireInformation(tire, 4);
    tirePressure(tire, 4);
    tireTest(tire, 4);

    return 0;
} // end main