【发布时间】:2017-05-03 19:12:44
【问题描述】:
所以我已经制作了一个工作程序,用于从文件中获取数据并根据您希望在 main 中的文件的哪一部分打印出文件。但我的目标是通过创建用户界面并从文件中附加到链接列表或根据要求打印出该链接列表的一部分(如果有)来使这个模块化。 只有一个问题:我似乎无法找到一种方法来成功地将链表传递给函数,这样当你在函数中创建新节点(附加)时,它也可以在 main 中工作,然后在 (打印)。
这是工作代码:
#include <stdio.h>
#include <stdlib.h> /* has the malloc prototype */
#define TSIZE 100 /* size of array to hold title */
struct book {
char title[TSIZE], author[TSIZE],year[6];
struct book * next; /* points to next struct in list */
};
//typedef struct book ITEM;
typedef struct book * Node; // struct book *
void Append(Node *List, Node *Lcurrent,char filename[]);
void ClearGarbage(void);
int main(void){
Node head=NULL;
Node current;
current=head;
char fname[]="HW15Data.txt";
char op;
do{
puts("Select operation from the following list:");
puts("a. Append p. Print q. quit");
op = getchar();
ClearGarbage();
if (op=='a'){
/* Gather and store information */
Append(&head,¤t,fname);
}
else if (op=='q'){
/* User quit, so free allocated memory */
current = head;
while (current != NULL)
{
free(current);
current = current->next;
}
printf("Bye!\n");
return 0;
}
else{
/* Program done, so free allocated memory */
current = head;
while (current != NULL)
{
free(current);
current = current->next;
}
printf("Invalid characted entered. Bye!\n");
return 0;
}
} while (op!='q');
return 0;
}
void Append(Node *List, Node * Lcurrent,char filename[TSIZE]){
FILE * fp;
Node head=*List;
Node current=*Lcurrent;
int loops=0;
fp=fopen(filename,"r");
if (head==NULL){
head=(Node) malloc(sizeof(struct book));
current=head;
current->next=NULL;
}
do{
current->next = (Node) malloc(sizeof(struct book));
current=current->next;
loops++;
} while(fgets(current->title,sizeof(current->title),fp) && fgets(current->author,sizeof(current->title),fp) && fgets(current->year,sizeof(current->year),fp));;
free(current);
printf("Number of records written: %d\n",loops);
//Same as Print function in the nonworking code
int num;
int i=0;
if (head == NULL){
printf("No data entered. ");
}
else{
printf("Enter record # to print: ");
scanf("%d",&num);
ClearGarbage();
num=num+1;
current = head;
while (current != NULL && i<num)
{
for (i=0;i<num;i++)
current = current->next;
printf("Book: %sAuthor: %sYear: %s\n",
current->title, current->author, current->year);
}
}
}
void ClearGarbage(void){
while (getchar()!='\n');
}
好吧,这很有效,但我的猜测是,一旦 Append 完成,在 Append 中创建的节点在 main 中就没有用了,因为它们现在已经消失了。所以当我尝试在下面的代码中创建一个打印函数时,没有什么可以打印的。
#include <stdio.h>
#include <stdlib.h> /* has the malloc prototype */
#define TSIZE 100 /* size of array to hold title */
struct book {
char title[TSIZE], author[TSIZE],year[6];
struct book * next; /* points to next struct in list */
};
//typedef struct book ITEM;
typedef struct book * Node; // struct book *
void Append(Node *List, Node *Lcurrent,char filename[]);
int Print(Node *List,Node *Lcurrent);
void ClearGarbage(void);
int main(void){
Node head=NULL;
Node current;
current=head;
char fname[]="HW15Data.txt";
char op;
do{
puts("Select operation from the following list:");
puts("a. Append p. Print q. quit");
op = getchar();
ClearGarbage();
if (op=='a'){
/* Gather and store information */
Append(&head,¤t,fname);
}
else if (op=='p'){
/*Print book record of user's choice*/
Print(&head,¤t);
}
else if (op=='q'){
/* User quit, so free allocated memory */
current = head;
while (current != NULL)
{
free(current);
current = current->next;
}
printf("Bye!\n");
return 0;
}
else{
/* Program done, so free allocated memory */
current = head;
while (current != NULL)
{
free(current);
current = current->next;
}
printf("Invalid characted entered. Bye!\n");
return 0;
}
} while (op!='q');
return 0;
}
void Append(Node *List, Node * Lcurrent,char filename[TSIZE]){
FILE * fp;
Node head=*List;
Node current=*Lcurrent;
int loops=0;
fp=fopen(filename,"r");
if (head==NULL){
head=(Node) malloc(sizeof(struct book));
current=head;
current->next=NULL;
}
do{
current->next = (Node) malloc(sizeof(struct book));
current=current->next;
loops++;
} while(fgets(current->title,sizeof(current->title),fp) && fgets(current->author,sizeof(current->title),fp) && fgets(current->year,sizeof(current->year),fp));
free(current);
printf("Number of records written: %d\n",loops);
}
int Print(Node *List,Node *Lcurrent){
int num;
int i=0;
Node head=*List;
Node current=*Lcurrent;
if (head == NULL){
printf("No data entered.\n");
return -1;
}
printf("Enter record # to print: ");
scanf("%d",&num);
ClearGarbage();
num=num+1;
current = head;
while (current != NULL && i<num)
{
for (i=0;i<num;i++){
current = current->next;
}
printf("Book: %sAuthor: %sYear: %s\n",
current->title, current->author, current->year);
}
return 0;
}
void ClearGarbage(void){
while (getchar()!='\n');
}
感谢任何人的帮助!
编辑:为了清楚起见,去掉了一个未使用的 typedef
【问题讨论】:
-
嗯,像
typedef struct book * Node;这样的点的类型定义在某些编码风格中是不受欢迎的做法。 -
typedef struct Node List;这还有效吗? -
@chux 我认为
typedef struct Node List正在创建一个不完整的类型struct Node并将其类型定义为List。与上一行的Node无关。 -
无论如何
List类型不在任何地方使用。这只会造成混乱。 -
@chux 你说得对,后来我被
while和for弄糊涂了。
标签: c function linked-list