具有结构的数组的逻辑

Question

我很难在下面的代码中实现新员工介绍逻辑。通过确定新数量并根据它重新定位向量，第一个新员工会提前或迟到或程序正在终止。

 #include <stdio.h>
 #include <stdlib.h>

 typedef struct {
char * name;
char * email;
int age;
}Employee;

   int main () {

 int i, option, employeeInitialQuantity, newEmployeeQuantity;

 printf ("How many employees would you like to register?");
scanf ("%d", &employeeInitialQuantity);
Employee *employees = malloc (employeeInitialQuantity * sizeof (Employee));

 for (i = 0; i < employeeInitialQuantity; i++) {

    employees [i] .name = malloc (35);
    printf ("\nType employee name %d:", i);
    scanf ("%34s", employees[i].name);
    printf ("\n%s", employees [i].name);
    employees [i] .email = malloc (35);
    printf ("\nEnter Employee Email% d:", i);
    scanf ("%34s", employees [i].email);
    printf ("\n%s", employees [i].email);
    printf ("\nEnter employee age %d:", i);
    scanf ("%d", & employees [i].age);
    printf ("\n%d", employees [i].age);
}



    while (1) {

     printf ("1.Register more employees \n");
     printf ("2.List employees \n");
     printf ("3.Edit employee data \n");
     printf ("4.Delete Employee \n");
     scanf ("%d", &option);

     if (option == 1) {

    printf ("Do you want to register how many more employees?");
    scanf ("%d", &newEmployeeQuantity);


   employees = (Employee *) realloc (employees, newEmployeeQuantity * sizeof (Employee));

   for (i =  employeeInitialQuantity; i <= newEmployeeQuantity; i ++) {

  employees [i] .name = malloc (35);
   printf ("\nType employee name% d:", i);
   scanf ("%34s", employees [i] .name);
   printf ("\n%s", employees [i] .name);
   employees [i] .email = malloc (35);
   printf ("\nEnter Employee Email %d:", i);
   scanf ("%34s", employees [i].email);
   printf ("\n%s", employees [i].email);
   printf ("\nEnter employee age %d:", i);
   scanf ("%d", & employees[i] .age);
   printf ("\n%d", employees[i].age);
}
        employeeInitialQuantity = (employeeInitialQuantity + newEmployeeQuantity) -1;

}




 else if (option == 3) {

       printf ("Enter the employee number you wish to edit:");
       int number;
       scanf ("%d", & number);
       printf ("Enter new employee name% d:", number);
       scanf ("%34s", employees [number] .name);
       printf ("Enter new employee email% d:", number);
       scanf ("%34s", employees [number] .email);
       printf ("Enter new employee age %d:", number);
       scanf ("%d\n", & employees [number]. age);

 }

}

  return 0;

}

enter image description here

我正在尝试执行此语句：

制作一个管理员工（姓名、年龄、电子邮件）的程序。该程序应显示用户菜单， 有以下选项：

1. 注册

A.该程序应该允许包含新员工，询问用户他想要包含多少新员工并将他们注册到员工数组中；

B.值得注意的是，应根据需要分配员工数组，避免 浪费内存；

C.名称和电子邮件字符串也必须动态分配，数组也应如此 员工。

1. 列表

A.程序应显示注册员工列表，每行一个，用“------”分隔 --------------------- "。列表应在每一行显示姓名、电子邮件和年龄 如下：“姓名 - email@gmail.com - 25”。

1. 编辑：

A.该程序应允许编辑特定员工。为此，应允许编辑。 来自员工在员工数组中的索引，或通过姓名搜索或 员工的电子邮件。

4. 删除

A.该计划应允许排除特定员工。为此，应允许 从员工数组中的索引中删除员工，或从搜索中删除员工 员工姓名。

B.删除员工后，应重新排列数组，使其没有“漏洞”。

Answer 1

您没有正确重新分配，在第二个参数或 realloc 中，您需要提供所需的总内存，而不仅仅是额外的内存

代码如下：

#include <stdio.h>
#include <stdlib.h>

typedef struct
{
    char *name;
    char *email;
    int age;
} Employee;

int main ()
{
    int i, option, employeeInitialQuantity, newEmployeeQuantity;

    printf("How many employees would you like to register?");
    scanf("%d", &employeeInitialQuantity);
    Employee *employees = malloc(employeeInitialQuantity * sizeof (Employee));

    for (i = 0; i < employeeInitialQuantity; i++)
    {
        employees[i].name = malloc(35);
        printf("\nType employee name %d:", i);
        scanf("%34s", employees[i].name);
        printf("\n%s", employees[i].name);
        employees[i].email = malloc(35);
        printf("\nEnter Employee Email %d:", i);
        scanf("%34s", employees[i].email);
        printf("\n%s", employees[i].email);
        printf("\nEnter employee age %d:", i);
        scanf("%d", &employees[i].age);
        printf("\n%d\n\n", employees[i].age);
    }

    while (1)
    {
        printf("1.Register more employees \n");
        printf("2.List employees \n");
        printf("3.Edit employee data \n");
        printf("4.Delete Employee \n");
        scanf("%d", &option);

        if (option == 1)
        {
            printf("Do you want to register how many more employees?");
            scanf("%d", &newEmployeeQuantity);

            employees = (Employee *)realloc(employees, (employeeInitialQuantity + newEmployeeQuantity) * sizeof(Employee));

            for (i =  employeeInitialQuantity; i < (employeeInitialQuantity + newEmployeeQuantity); i ++)
            {
                employees[i].name = malloc(35);
                printf("\nType employee name% d:", i);
                scanf("%34s", employees[i].name);
                printf("\n%s", employees[i].name);
                employees[i].email = malloc(35);
                printf("\nEnter Employee Email %d:", i);
                scanf("%34s", employees[i].email);
                printf("\n%s", employees[i].email);
                printf("\nEnter employee age %d:", i);
                scanf("%d", &employees[i].age);
                printf("\n%d\n\n", employees[i].age);
            }
            employeeInitialQuantity = (employeeInitialQuantity + newEmployeeQuantity);
        }

        else if (option == 3)
        {
            printf ("Enter the employee number you wish to edit:");
            int number;
            scanf ("%d", & number);
            printf ("Enter new employee name% d:", number);
            scanf ("%34s", employees[number].name);
            printf ("Enter new employee email% d:", number);
            scanf ("%34s", employees[number].email);
            printf ("Enter new employee age %d:", number);
            scanf ("%d\n", &employees[number].age);
        }
    }
    return 0;
}