【发布时间】:2019-03-22 08:16:05
【问题描述】:
我正在尝试为 2D FFT 编写 C 程序。这个想法是使用预先分配的内存传递结构指针,函数将在其中修改这些内存地址。
complex_num 是一个支持复数运算的结构,如加法、减法、乘法、除法、幂、复指数。我放置 printf("Hello\n"); 的地方语句是我的代码中发生分段错误的地方。感谢期待。
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
typedef struct complex_num_struct {
double real;
double imag;
} complex_num;
complex_num add(complex_num num1, complex_num num2);
complex_num subtract(complex_num num1, complex_num num2);
complex_num multiply(complex_num num1, complex_num num2);
complex_num divide(complex_num num1, complex_num num2);
complex_num power(complex_num num, double n);
complex_num complex_exp(double theta);
double magnitude(complex_num num);
void display_complex_matrix(complex_num** matrix, int height, int width);
void fft2(complex_num** input, complex_num** output, int height, int width);
void fft_driver(complex_num input[], complex_num output[], int n, int step);
void fft(complex_num input[], complex_num output[], int n);
void display_complex_vec(complex_num * vec, int n);
complex_num conjugate(complex_num num);
complex_num ** matrix;
complex_num ** temp;
void main() {
complex_num one;
one.real = 1;
one.imag = 0;
complex_num height, width;
height.real = 4;
width.real = 4;
height.imag = 0;
width.imag = 0;
complex_num zero;
zero.real = 0;
zero.imag = 0;
complex_num input1[] = {one, one, one, one};
complex_num input2[] = {one, one, one, one};
complex_num input3[] = {zero, zero, zero, zero};
complex_num input4[] = {zero, zero, zero, zero};
complex_num* input[] = {input1, input2, input3, input4};
complex_num* output[] = {input1, input2, input3, input4};
complex_num* conj[] = {input1, input2, input3, input4};
fft2(input, output, 4, 4);
display_complex_matrix(output, 4, 4);
for (int i = 0; i < 4; ++i) {
for (int j = 0; j < 4; ++j) {
conj[i][j] = conjugate(output[i][j]);
}
}
fft2(conj, output, 4, 4);
for (int i = 0; i < 4; ++i) {
for (int j = 0; j < 4; ++j) {
output[i][j] = conjugate(divide(conj[i][j], (multiply(height, width))));
}
}
display_complex_matrix(output, 4, 4);
}
void fft2(complex_num** input, complex_num** output, int height, int width) {
matrix = (complex_num **) malloc(height * sizeof(complex_num*));
temp = (complex_num **) malloc(width * sizeof(complex_num*));
for (int i = 0; i < height; ++i) {
fft(input[i], temp[i], width);
}
for (int i = 0; i < height; ++i) {
//matrix[i] = (complex_num*) malloc(height * sizeof(complex_num));
for (int j = 0; j < width; ++j) {
//matrix[i][j] = temp[j][i];
printf("%lf", temp[j][i].real);
}
}
for (int i = 0; i < height; ++i) {
fft(matrix[i], temp[i], width);
}
for (int i = 0; i < height; ++i) {
for (int j = 0; j < width; ++j) {
output[i][j] = temp[j][i];
}
}
}
void display_complex_vec(complex_num vec[], int n) {
printf("[");
for (int i = 0; i < n; ++i) {
printf("(%g, %g), ", vec[i].real, vec[i].imag);
}
printf("]\n");
}
void display_complex_matrix(complex_num** matrix, int height, int width) {
for (int i = 0; i < height; ++i) {
printf("[");
for (int j = 0; j < width; ++j) {
printf("(%g, %g), ", matrix[i][j].real, matrix[i][j].imag);
}
printf("]\n");
}
}
void fft_driver(complex_num input[], complex_num output[], int n, int step) {
complex_num diff, cexp;
if (step < n) {
fft_driver(output, input, n, step * 2);
fft_driver(output + step, input + step, n, step * 2);
for (int i = 0; i < n; i += 2 * step) {
cexp = complex_exp(-M_PI * (double) i / (double) n);
diff = multiply(complex_exp(-M_PI * (double) i / (double) n), output[i + step]);
input[i / 2] = add(output[i], diff);
input[(i + n) / 2] = subtract(output[i], diff);
//printf("(%g, %g) * (%g, %g)\n", input[i / 2].real, input[i / 2].imag, input[(i + n) / 2].real, input[(i + n) / 2].imag);
}
}
}
void fft(complex_num* input, complex_num* output, int n) {
complex_num* dummy = (complex_num *)malloc(n * sizeof(complex_num));
complex_num* inp = (complex_num *)malloc(n * sizeof(complex_num));
for (int i = 0; i < n; ++i) {
dummy[i].real = 0;
dummy[i].imag = 0;
inp[i].real = 0;
inp[i].imag = 0;
}
printf("%lf", inp[1].real);
for (int i = 0; i < n; ++i) {
dummy[i] = input[i];
inp[i] = input[i];
}
fft_driver(inp, dummy, n, 1);
printf("Hello\n");
for (int i = 0; i < n; ++i) {
output[i] = inp[i];
}
}
complex_num complex_exp(double theta) {
complex_num result;
result.real = cos(theta);
result.imag = sin(theta);
return result;
}
double magnitude(complex_num num) {
return sqrt(pow(num.real, 2) + pow(num.imag, 2));
}
complex_num add(complex_num num1, complex_num num2) {
complex_num result;
result.real = num1.real + num2.real;
result.imag = num1.imag + num2.imag;
return result;
}
complex_num conjugate(complex_num num) {
complex_num result;
result.real = num.real;
result.imag = -num.imag;
return result;
}
complex_num subtract(complex_num num1, complex_num num2) {
complex_num result;
result.real = num1.real - num2.real;
result.imag = num1.imag - num2.imag;
return result;
}
complex_num multiply(complex_num num1, complex_num num2) {
complex_num result;
result.real = num1.real * num2.real - num1.imag * num2.imag;
result.imag = num1.real * num2.imag + num1.imag * num2.real;
return result;
}
complex_num divide(complex_num num1, complex_num num2) {
complex_num result;
double magnitude_square = pow(num2.real, 2) + pow(num2.imag, 2);
num2.imag = -num2.imag;
result = multiply(num1, num2);
result.real = result.real / magnitude_square;
result.imag = result.imag / magnitude_square;
return result;
}
complex_num power(complex_num num, double n) {
complex_num result;
double magnitude = sqrt(pow(num.real, 2) + pow(num.imag, 2));
result.real = pow(magnitude, n) * cos(n * atan(num.imag / num.real));
result.imag = pow(magnitude, n) * sin(n * atan(num.imag / num.real));
return result;
}
以上代码产生以下输出:
0.000000Hello
Segmentation fault (core dumped)
在调试的时候,发现段错误发生在循环中我的代码的以下函数中,就在printf语句之后:
void fft(complex_num* input, complex_num* output, int n) {
complex_num* dummy = (complex_num *)malloc(n * sizeof(complex_num));
complex_num* inp = (complex_num *)malloc(n * sizeof(complex_num));
for (int i = 0; i < n; ++i) {
dummy[i].real = 0;
dummy[i].imag = 0;
inp[i].real = 0;
inp[i].imag = 0;
}
printf("%lf", inp[1].real);
for (int i = 0; i < n; ++i) {
dummy[i] = input[i];
inp[i] = input[i];
}
fft_driver(inp, dummy, n, 1);
printf("Hello\n");
for (int i = 0; i < n; ++i) {
output[i] = inp[i];
}
}
所需的输出应如下所示:-
0.000000Hello
0.000000Hello
0.000000Hello
0.000000Hello
4.0000004.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.0000000.000000Hello
0.000000Hello
0.000000Hello
0.000000Hello
[(8, 0), (0, 0), (0, 0), (0, 0), ]
[(4, -4), (0, 0), (0, 0), (0, 0), ]
[(0, 0), (0, 0), (0, 0), (0, 0), ]
[(4, 4), (0, 0), (0, 0), (0, 0), ]
0.000000Hello
0.000000Hello
0.000000Hello
0.000000Hello
4.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000004.0000000.000000Hello
0.000000Hello
0.000000Hello
0.000000Hello
[(1, 1), (1, 1), (1, 1), (1, 1), ]
[(0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), ]
[(0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), ]
[(0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), (0.0625, -0.0625), ]
【问题讨论】:
-
您可以使用调试器找到此类错误——只需运行代码直至崩溃,然后查看您所在的位置并检查数据。你会看到
output是fft中的一个空指针,因为你只为fft2中的二维temp数组的第一级分配了内存。 -
至少你在 fft_driver() 中访问
output[i + step]可能大于n。你调用fft_driver(output + step, input + step, n, step * 2);,其中 output+step 是一个较小的数组,但 n 没有减少。