【发布时间】:2011-02-07 21:58:10
【问题描述】:
我正在研究如何在调用函数 timer_create() 时获取线程 ID。 我观察到每次调用 timer_create() 时,都会创建一个新线程(主进程的子线程)。我用 ps -eL|grep 验证了这一点
我需要在使用 timer_create 的程序中获得由 ps -eL 显示的相同 TID(子线程 ID)。 从下面的代码:如何在我的程序中获取 TID 18018?
我研究了所有帖子,每个帖子都提到在调用通知函数而不是调用 timer_create() 时创建了一个新线程。
非常感谢您的帮助!
代码:
SLGTRACER_DEFINE(testMain, "testMain");
timer_t audit_timer1;
void timeoutHandler(sigval_t info)
{
slgInfo(testMain, "timeoutHandler invoked");
slgInfo(testMain, "gettid() = %lu TESTMAIN", syscall(SYS_gettid));
slgInfo(testMain, "getpid() = %d TESTMAIN", getpid());
}
int main(void)
{
slgInfo(testMain, "testMain Invoked");
struct sigevent evp1;
evp1.sigev_notify = SIGEV_THREAD;
evp1.sigev_value.sival_ptr = &audit_timer1;
evp1.sigev_notify_function = timeoutHandler;
evp1.sigev_notify_attributes = NULL;
const int ERROR_BUFFER_SIZE = 50;
slgInfo(testMain, "Before FIRST timer_create");
sleep(30);
// Create timer thread
if (timer_create(CLOCK_REALTIME, &evp1, &audit_timer1) != 0)
{
// Character buffer for storing error message.
char errBuff[ERROR_BUFFER_SIZE];
memset(errBuff, 0, ERROR_BUFFER_SIZE);
slgError(testMain,
"timer_start create failed. Error = %s",
strerror_r(errno, errBuff, ERROR_BUFFER_SIZE));
timer_delete(audit_timer1);
bzero(&audit_timer1, sizeof(audit_timer1));
}
slgInfo(testMain, "After FIRST timer_create");
sleep(30);
return 0;
}
bash-3.1# ps -eL|grep testM
16651 16651 pts/0 00:00:00 testMain
16651 18018 pts/0 00:00:00 testMain
child thread with ID created by timer_create() = 18018
【问题讨论】:
标签: c++ c linux multithreading