如何从猫鼬中获取类型化的对象答案

【问题标题】：How to get typed object from mongoose如何从猫鼬中获取类型化的对象
【发布时间】：2021-01-03 20:24:25
【问题描述】：

我在 typescript 中有一个 nodejs 应用程序，我最近开始使用 mongoose 来查询 mongo db，但我正在努力寻找一种从 findById 方法获取类型化对象的方法。有没有办法通过某种方式从该方法中获取类型化对象？

import * as mongoose from 'mongoose';
export const LinksCacheSchema = new Schema({
    ts: {
        type: Date,
        default: Date.now()
    },
    imdbId: String,
    parentLink: String,
    playableLink: String,
    status: String,
    title: String,
    size: Number,
    contentType: String,
}, { collection: 'links_cache' });

export const LinksCacheList = mongoose.model('LinksCache', LinksCacheSchema);


const linkInfo = await LinksCacheList.findById(documentId); //this is the one returning type of any instead of LinksCacheSchema or any specific type

【问题讨论】：

标签： node.js mongodb typescript mongoose mongoose-schema

【解决方案1】：

您可以为该架构创建和导出接口：

import mongoose, { Schema, Document, Model } from 'mongoose';

export interface ILinksCacheSchema extends Document {
    ts: Date,
    imdbId: string,
    parentLink: string,
    playableLink: string,
    status: string,
    title: string,
    size: number,
    contentType: string,
}

const LinksCacheSchema = new Schema({
    ts: {
        type: Date,
        default: Date.now()
    },
    imdbId: String,
    parentLink: String,
    playableLink: String,
    status: String,
    title: String,
    size: Number,
    contentType: String,
}, { collection: 'links_cache' });

export const LinksCacheList: Model<ILinksCacheSchema> = mongoose.model('LinksCache', LinksCacheSchema);

// in your app logic
const linkInfo = await LinksCacheList.findById(documentId);

两次创建架构可能会有点乏味，所以我建议你看看这个：

https://www.npmjs.com/package/ts-mongoose

【讨论】：