我正在创建一个基于文本的冒险游戏，需要替代使用 GOTO

Question

如何正确使用 do、while 或 for 循环来防止用户输入答案“1”或“2”以外的任何其他内容？

如果他们不这样做，程序应该告诉他们他们不能这样做，然后让他们回到上一个问题。

#include <iostream>
#include "Options.h"
#include <string>

using namespace std;

int main(int argc, char *argv[]) {
    cout << "\tWelcome to my text adventure game\n" << endl;
    cout << "Please enter your characters Name: ";
    string name;
    cin >> name;
    cout  << "\nWelcome " << name << endl;
    cout << "\nPlease choose the side you would like to play in - ";
    Options OptionsObject;
    OptionsObject.optionsSide();

    string answer;
    while(answer != "quit") {
        cin >> answer;
        cout << answer << endl;
    }

    if ( answer == "1" ) {
        cout << "You chose the good side. Let the game begin\n "  << endl;
        cout << "You are located in a city named after the warrior who saved it from the evil\nmany years ago. The city of Redshore. " << endl;
        cout << "You are no ordinary man in the City of Redshore. You are the king who rules it\nYou are seen as King of Justice, a good king.\nOne who only want what is best for his people" << endl;
        cout << "but also a troubled man. You experienced something traumatizing when you\nwere a just a little boy, but no one knows about it,\nno one but yourself that is  " << endl;
    } else if( answer == "2" ) {
        cout << "hey there" << endl;
    }
}

Answer 1

看到这个问题会出现在用户在游戏过程中会做的所有选择中，我会做一个外部函数，让用户选择。也许是一个以这种方式工作的静态类。

int ans = Answer.getUserAnswer(2,"[1/2]>");

这应该以这种方式工作：

public static int getUserAnswer(int max =1,string message="[1/1]>")
{
    int ans = 0;
    while(ans==0){
        cout<<message<<" ";
        cin >> answer;
        if(answer>0 and answer<=max) return ans;
        cout<<"\tnot a valid choose\n";
        ans=0;
    }
}

并且您将在您的 ans 中获得您期望的值之一，如果答案不在您期望的值之间，它将打印“无效选择”，即使有 10 个答案，您也可以这样做，调用它默认情况下，希望您只给他第一名。

我在自己制作的主机游戏中使用了它；） 希望有用

编辑

int getUserAnswer(int max =1,string message="[1/1]>")
{
    int ans = 0;
    while(ans==0){
        cout<<message<<" ";
        cin >> answer;
        if(answer>0 and answer<=max) return ans;
        cout<<"\tnot a valid choose\n";
        ans=0;
    }
}

并在您的代码中请求此代码：

cout  << "\nWelcome " << name << endl;
    cout << "\nPlease choose the side you would like to play in - ";
    Options OptionsObject;
    OptionsObject.optionsSide();

    int answer =getUserAnswer(2,"[1/2]>");

    if (answer == 1){

cout << "You chose the good side. Let the game begin\n "  << endl; cout << "You are located in a city named after the warrior who saved it from the evil\nmany years ago. The city of Redshore. " << endl; cout << "You are no ordinary man in the City of Redshore. You are the king who rules it\nYou are seen as King of Justice, a good king.\nOne who only want what is best for his people" << endl; cout << "but also a troubled man. You experienced something traumatizing when you\nwere a just a little boy, but no one knows about it,\nno one but yourself that is  " << endl;
    }

    else if(answer == 2){

        cout << "hey there" << endl;

    }

Answer 2

您应该将读取输入的行放在一个 do 循环中，该循环在用户给出的答案无效时循环。

所以，你的 do 循环应该是：

string answer;

cin >> answer;

// loop while answer is neither "1" nor "2"
while( answer != "1" && answer != "2" ) {
    cout << "Please enter a 1 or a 2. You entered " << answer << endl;
    cin >> answer;
}