带有数组数据的jqgrid中的分页问题

Question

我在 jqgrid 中遇到了分页问题，​​数组数据有 18 条记录，但即使我指定了 pagination:true,pager:jQuery('#pager1')，这些记录也没有显示在页面中。你能帮我实现分页而不是滚动吗？

<script type="text/javascript">
 jQuery("#list4").jqGrid({
 datatype: "clientSide",
 height: 200,
    colNames:['Inv No','Date', 'Client', 'Amount','Tax','Total','Notes'],
    colModel:[
    {name:'id',index:'id', width:60, sorttype:"int"},
    {name:'invdate',index:'invdate', width:90, sorttype:"date"},
    {name:'name',index:'name', width:100},
    {name:'amount',index:'amount', width:80, align:"right",sorttype:"float"},
    {name:'tax',index:'tax', width:80, align:"right",sorttype:"float"},
    {name:'total',index:'total', width:80,align:"right",sorttype:"float"},
    {name:'note',index:'note', width:150, sortable:false}
    ],
    multiselect: true,
 pagination:true,
  pager:jQuery('#pager1'), 
 rowNum: 10,
 rowList: [5, 10, 20, 50],
 sortname: 'id',   
 sortorder: 'asc',
 viewrecords: true,
 page: 1,
 loadonce: true,  
 totalpages: 2,   
 totalrecords:18,     
 showpage:true,   
 imgpath: "/themes/default/images",         
 caption: "Manipulating Array Data"
 });
 var mydata = [
 {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"3",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"4",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"5",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"6",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"7",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"8",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"9",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"10",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"11",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"12",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"13",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"14",invdate:"2007-10-05",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"15",invdate:"2007-09-06",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},
 {id:"16",invdate:"2007-10-04",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
 {id:"17",invdate:"2007-10-03",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"},
 {id:"18",invdate:"2007-09-01",name:"test3",note:"note3",amount:"400.00",tax:"30.00",total:"430.00"},

 ];
 for(var i=0;i<=mydata.length;i++)   
 jQuery("#list4").addRowData(i+1,mydata[i]);

Answer 1

您的主要问题是您应该在添加大量行后重置rowNum。线

jQuery("#list4").setGridParam({ rowNum: 10 }).trigger("reloadGrid");

在您的代码末尾将解决问题。我建议您添加该行

jQuery("#list4").jqGrid('navGrid','#pager1',{edit:false,add:false,del:false});

直接在jqGrid之后定义。然后，您不仅可以进行数据分页，还可以进行数据过滤（搜索）和刷新（重置过滤器）。

再补充几点：

• 在 mydata 数组的定义中，您应该在 ']' 之前删除 ','。
• 在 for 循环中，您应该使用 i<mydata.length 而不是 i<=mydata.length。
• 您应该从 jqGrid 的定义中删除以下参数，这些参数要么不存在（如pagination），要么在上下文中没有意义（如loadonce: true）：pagination，page，loadonce， totalpages、totalrecords、showpage、imgpath。

如果您根据data: myData 参数构造jqGrid，或者一次设置来自mydata 的所有数据（参见http://www.trirand.com/jqgridwiki/doku.php?id=wiki:retrieving_data#array_data 中addRowData 方法的描述），您将获得最佳结果。

Answer 2

奥列格是正确的。 添加 jQuery("#list4").setGridParam({ rowNum: 10 }).trigger("reloadGrid"); 有效。

虽然如果 formatter 属性设置在 rowObject 值未定义的位置，它可能不起作用。（如果使用它们）

因此，请确保在您的格式化程序方法中，您始终检查它们的可用性。

例如

function getFormattedFileName(cellvalue, options, rowObject) {

        if(!rowObject.fileName) {// this is due to ...trigger("reloadGrid");
            return cellvalue; // the value is already formatted, let's just return it
        }
 return rowObject.fileName.trim();
}