检查某些文本的 message.content

Question

我正在尝试制作一个多项选择的琐事后台任务。我试图等待 client.wait_for_message 只为正确答案或不正确的选择。我正在检查 message.content 但我错过了一些东西，因为无论任何人输入什么，它都会显示“错误答案”，除非它是正确答案。如果有人输入的不是错误答案或正确答案，那么我希望它忽略他们的文字。

async def trivia_loop():
    await client.wait_until_ready()
    channel = client.get_channel("123456778999533")
    triviamonies = random.randint(1250, 2550)
    while not client.is_closed:
        await client.send_message(channel, '**Category**: {}\n**Difficulty**: {}\n\n{}\n\n**Potential Answers:**\n{}'.format(category, formatdiff, formatquestion, '\n'.join(tup)))
        winner = ''
        def check(m):
            return m.content.lower() == formatanswer.lower() and m.content.lower() != incorrectanswer1 or incorrectanswer2 or incorrectanswer3
        while winner == '':
            answerid = await client.wait_for_message(timeout=420, channel=channel, check=check)
            if answerid is None:
                winner = 1
                await client.delete_message(questionsend)
                await client.send_message(channel, 'No one answered correctly! The answer was {}'.format(formatanswer))
                await asyncio.sleep(840)
            elif get_triviaguessesTaken(answerid.author) < 1 and answerid.content.lower() == formatanswer.lower():
                winner = 1
                await client.delete_message(questionsend)
                await client.send_message(channel, '**{}** is correct!\n{} earns **${:,}** !'.format(formatanswer, answerid.author.mention, triviamonies))
                add_dollars(answerid.author, triviamonies)
                add_trivias(answerid.author, 1)
                await asyncio.sleep(900)
            elif get_triviaguessesTaken(answerid.author) < 1 and answerid.content.lower() == incorrectanswer1 or incorrectanswer2 or incorrectanswer3:
                await client.send_message(channel, '**{}** that is incorrect! Please try again on the next trivia question'.format(answerid.author.mention))
                add_triviaguessesTaken(answerid.author, 1)
            elif get_triviaguessesTaken(answerid.author) > 0 and answerid.content.lower() == incorrectanswer1 or incorrectanswer2 or incorrectanswer3:
                await client.send_message(channel, '{} you have already tried to guess this trivia question. Try again on the next one!'.format(answerid.author.mention))

Answer 1

Discord.py 版本：

从您的代码的外观来看，您仍在使用 d.py (v0.16.12) 的异步版本，并且您还没有迁移到更新和稳定的 rewrite version of d.py。

我强烈建议为最新的稳定版本运行 pip install --upgrade discord.py。确保你这样做并尽快重写你的代码，因为当你有更少的代码可以使用时，它会减少你的痛苦。

Wait_for() 重写中的用法：

文档在 on_message 事件中使用了一个示例，但我将在此处使用命令来创建一个示例以适应您的情况，因此您可以使用两种方法并且可以混合搭配：

@bot.command(aliases=["trivia"])
async def starttrivia(ctx):
    answers = ["paris", "london", "oslo"]
    await ctx.send(f"What's the capital of France?\n\n*Potential answers:*\n{', '.join(answers)}")
    correct = False
    
    def check(m):
        for a in answers:
            if a in m.content.lower():
                return True

    while not correct:
        try:    
            reply = await bot.wait_for("message", check=check, timeout=30)
            if "paris" in reply.content.lower():
                await ctx.send(f"Correct! {reply.author.mention} got the right answer!")
                correct = True
            else:
                await ctx.send("Incorrect, try again!")
        except asyncio.TimeoutError: # exception thrown when no reply is sent in time
            await ctx.send("Nobody guessed for 30 seconds! The answer was: Paris")
            break