我做了一个循环，现在我想在汇编中总结我的结果答案

【问题标题】：i made a loop that did calculations now i want to sum my results in assembly我做了一个循环，现在我想在汇编中总结我的结果
【发布时间】：2019-10-24 23:16:41
【问题描述】：

我们的任务是从用户那里获取 5 个输入

输入的数字应该从 9 中减去，然后我们应该合计所有的总差

例如输入 5,2,4,7,1 9-5= 4 , 9-2=7, 9-4=5, 9-7= 2, 9-1= 8 那么我们需要将结果相加，所以 4+7+5+2+8= 26

并显示结果

我已经进行了计算并将它们放在一个循环中，但总和只显示最后一次计算的值而不是总和

.model small
.stack 100h
.data

 num1 db
 num2 db 9
 result db ?
 sum db

 msg1 db 10, 13,"Enter a number: $", 10, 13
 msg2 db 10, 13,"Difference is: $",10, 13
 msg3 db 10, 13,"Sum is: $",10, 13

 .code
     main proc

     mov ax, @data
        mov ds, ax

        mov cx,5

        process:

        mov dx, offset msg1
        mov ah,9 ; used to print the string/msg with
        int 21h ;this



        mov ah, 1 ;READ a Character from Console,
                  ;Echo it on screen and save the
                  ;value entered in AL register
        int 21h

        sub al, 30h ;keep the value enter in bcd form
        mov num1, al ;move num1 to al
        ;al is used for input


        ;sub al, 30h
        mov al, num2 ;move num2 to al

        sub al, num1 ;

        mov result, al ;move whats in al to result


        mov bl,al
        add sum,bl
        ;add al,sum

        mov ah,0 ;clears whats in ah
        aaa ;used to convert the result to bcd
        ;and first digit is stored in ah
        ;second digit stored in al


        add ah, 30h ;convert whats in ah to ascii by adding 30h
        add al, 30h ;convert whats in al to ascii by adding 30h
        mov bx, ax ;saving whats in ah and al in bx register



        mov dx, offset msg2
        mov ah,9 ; used to print the string/msg  
        int 21h



        ;the following is used to print whats in the bh register
        ;dl is used for output
        ;2 or 2h means to write/print whats in dl
        ;so the value to be printed is moved to dl
        mov ah,2
        mov dl, bh
        int 21h


        ;the following is used to print whats in bl
        mov ah,2
        mov dl, bl
        int 21h

        loop process

        mov dx, offset msg3
        mov ah,9 ; used to print the string/msg  
        int 21h

        mov ah,2
        mov dl, bh
        int 21h


        ;the following is used to print whats in bl
        mov ah,2
        mov dl, bl
        int 21h

     mov ah, 4ch ;4ch means to return to OS i.e. the end
     ;of program
     int 21h
    main endp ;ends the code
end main ;ends main

我的预期是 26。相反，我得到 8

【问题讨论】：

标签： assembly dos x86-16

【解决方案1】：

sum db

这缺少一个操作数。写sum db 0

但是总和只显示最后一次计算的值而不是总和

在显示第 3 条消息和对应的值之间，您忘记重新计算 BX 所需的内容。您只需重新使用已经存在的内容！

    mov dx, offset msg3
    mov ah, 09h
    int 21h

    mov al, sum         ADD THIS
    mov ah, 0           ADD THIS
    aaa                 ADD THIS
    add ax, 3030h       ADD THIS
    mov bx, ax          ADD THIS

    mov ah, 02h
    mov dl, bh
    int 21h

    mov ah, 02h
    mov dl, bl
    int 21h

    mov ax, 4C00h
    int 21h

【讨论】：