判断一个词是否是回文答案

【问题标题】：Determining if a word is a palindrome or not判断一个词是否是回文
【发布时间】：2021-02-22 01:44:00
【问题描述】：

我确定一个单词是否为回文的代码如下。

word = str(input('Enter a word: '))
word = word.lower()
backwardsWord = word.lower()
for i in range(len(word) - 1, -1, -1)
    backwardsWord = backwardsWord + word[i]
    print(word + " in reverse is: " + backwardsWord)
    if backwardsWord == word:
        print("This word is a palindrome")
    elif backwardsWord != word:
        print("This word is not a palindrome")

当我运行程序时，它会一个字母一个字母地拼出单词，并确定该字母是否与最初输入的相同。例如，这是我使用雷达一词时的输出：

radar in reverse is: r
This word is not a palindrome
radar in reverse is: ra
This word is not a palindrome
radar in reverse is: rad
This word is not a palindrome
radar in reverse is: rada
This word is not a palindrome
radar in reverse is: radar
This word is a palindrome

我怎样才能使输出只输出最后两行而不是之前的两行？

【问题讨论】：

标签： python palindrome

【解决方案1】：

循环是不必要的：

word = str(input('Enter a word: '))
word = word.lower()
backwardsWord = word[::-1]
print(word + " in reverse is: " + backwardsWord)
if backwardsWord == word:
        print("This word is a palindrome")
elif backwardsWord != word:
    print("This word is not a palindrome")

如果您愿意，如果您认为更清楚，也可以使用backwardsWord = "".join(reversed(word))。

如果你还想保持显式循环：

word = str(input('Enter a word: '))
word = word.lower()
backwardsWord = ""
for i in range(len(word) - 1, -1, -1):
    backwardsWord = backwardsWord + word[i]
print(word + " in reverse is: " + backwardsWord)
if backwardsWord == word:
    print("This word is a palindrome")
elif backwardsWord != word:
    print("This word is not a palindrome")

【讨论】：

【解决方案2】：

将if ... elif语句放在循环体之后

【讨论】：