【发布时间】:2017-05-08 17:50:25
【问题描述】:
请解释一下推送功能。我不明白为什么要使用循环。对于 char 和 int (new_node->data=new_data) 工作正常。但对于 string ,它没有。对于 string ,会产生错误。如果在 push() 方法中为 new_data 打印 char(%c) 则只打印第一个字符,而如果为 new_node->data 打印 char(%c) 则打印最后一个字符。
// C program for generic linked list
#include<stdio.h>
#include<stdlib.h>
/* A linked list node */
struct node
{
// Any data type can be stored in this node
void *data;
struct node *next;
};
/* Function to add a node at the beginning of Linked List.
This function expects a pointer to the data to be added
and size of the data type */
void push(struct node** head_ref, void *new_data, size_t data_size)
{
// Allocate memory for node
struct node* new_node = (struct node*)malloc(sizeof(struct node));
new_node->data = malloc(data_size);
new_node->next = (*head_ref);
// Copy contents of new_data to newly allocated memory.
// Assumption: char takes 1 byte.
int i;
//Why loop is used for copying data from new_data to new_node data.
for (i=0; i<data_size; i++)
*(char *)(new_node->data + i) = *(char *)(new_data + i);
// Change head pointer as new node is added at the beginning
(*head_ref) = new_node;
}
/* Function to print nodes in a given linked list. fpitr is used
to access the function to be used for printing current node data.
Note that different data types need different specifier in printf() */
void printList(struct node *node, void (*fptr)(void *))
{
while (node != NULL)
{
(*fptr)(node->data);
node = node->next;
}
}
// Function to print an integer
void printInt(void *n)
{
printf(" %d", *(int *)n);
}
// Function to print a float
void printFloat(void *f)
{
printf(" %f", *(float *)f);
}
/* Driver program to test above function */
int main()
{
struct node *start = NULL;
// Create and print an int linked list
unsigned int_size = sizeof(int);
int arr[] = {10, 20, 30, 40, 50}, i;
for (i=4; i>=0; i--)
push(&start, &arr[i], int_size);
printf("Created integer linked list is \n");
printList(start, printInt);
// Create and print a float linked list
unsigned float_size = sizeof(float);
start = NULL;
float arr2[] = {10.1, 20.2, 30.3, 40.4, 50.5};
for (i=4; i>=0; i--)
push(&start, &arr2[i], float_size);
printf("\n\nCreated float linked list is \n");
printList(start, printFloat);
return 0;
}
【问题讨论】:
-
循环只是复制数据。它的作用类似于
memcpy(new_node->data, new_data, data_size);,这是因为您的链表旨在保存任何数据类型。在 C 中,这意味着原始字节和sizeofs。 -
/ Any data type can be stored in this node void *data;。嗯long double可能不适合。指向函数的指针也可能不适合。不过对于对象指针来说已经足够了。 -
指向
void*的指针算术运算也无效。 (它是 GCC 扩展) -
我想你想要像
*( ((char *)new_node->data) + i)这样的东西。memcpy()会更好。
标签: c data-structures