【发布时间】:2011-11-07 03:24:52
【问题描述】:
这里有一些上下文: 我正在处理一项任务,以折叠存储半边数据结构的网格中的边。这是直接相关的代码。
System.out.println("Initial Size: " +heds.faces.size());
if (! heds.faces.remove(currentHE.twin.leftFace));
{
System.out.println("We have a twin problem");
//this will always print
}
// Yet this will always be 1 less than the initial
System.out.println("After twin removal: " +heds.faces.size());
if ( !heds.faces.remove(currentHE.leftFace))
{
System.out.println("We have a problem");
}
System.out.println("Third: " +heds.faces.size());
所以问题是“我们有一个双胞胎问题”总是打印出来,但它不应该,但“去除双胞胎后”总是比初始大小小一。
如果您觉得需要,这里是其余信息。 heds 在“HEDS”类(半边数据结构)中定义:
public HEDS( PolygonSoup soup ) {
HalfEdge potentialTwin;
HalfEdge[] currHalfEdges;
Vertex curr, next;
for (int[] face : soup.faceList)
{
currHalfEdges = new HalfEdge[face.length];
for (int i = 0; i < face.length; i++)
{
HalfEdge he = new HalfEdge();
curr = soup.vertexList.get(face[i]);
next = soup.vertexList.get(face[(i+1)%face.length]);
he.tail = curr;
he.head = next;
currHalfEdges[i] = he;
halfEdges.put(face[i]+","+face[(i+1)%face.length], he);
potentialTwin = halfEdges.get(face[(i+1)%face.length]+","+face[i]);
if (potentialTwin != null)
{
he.twin = potentialTwin;
potentialTwin.twin = he;
}
}
for (int i = 0; i < currHalfEdges.length; i++)
{
currHalfEdges[i].next = currHalfEdges[(i+1)%currHalfEdges.length];
}
faces.add(new Face(currHalfEdges[0]));
}
// Checking if every half-edge's face was propery defined
Iterator<Entry<String, HalfEdge>> it = halfEdges.entrySet().iterator();
while (it.hasNext())
{
Map.Entry<String, HalfEdge> pairs = (Map.Entry<String, HalfEdge>)it.next();
if (!faces.contains(pairs.getValue().twin.leftFace))
{
System.out.println("DAMN IT!!!!!");
// This is never reached
}
}
此外,我是否先去除双胞胎的脸似乎并不重要。也可以假设此时网格是流形的。
半边:
public class HalfEdge {
public HalfEdge twin;
public HalfEdge next;
public Vertex head;
public Vertex tail;
public Face leftFace;
/**
* while perhaps wasting space, it may be convenient to
* have a common edge object for each pair of half edges to
* store information about the error metric, optimal vertex
* location on collapse, and the error
*/
public Edge e;
/** @return the previous half edge (could just be stored) */
public HalfEdge prev() {
HalfEdge prev = this;
while ( prev.next != this ) prev = prev.next;
return prev;
}
/**
* Computes the valence by walking around the vertex at head.
* @return valence of the vertex at the head of this half edge
*/
public int valence() {
HalfEdge loop = this;
int v = 0;
do {
v++;
loop = loop.next.twin;
} while ( loop != this );
return v;
}
人脸代码:
public class Face {
/** sure, why not keep a normal for flat shading? */
public Vector3d n = new Vector3d();
/** Plane equation */
Vector4d p = new Vector4d();
/** Quadratic function for the plane equation */
public Matrix4d K = new Matrix4d();
/** Some half edge on the face */
HalfEdge he;
/**
* Constructs a face from a half edge, and computes the flat normal
* @param he
*/
public Face( HalfEdge he ) {
this.he = he;
HalfEdge loop = he;
do {
loop.leftFace = this;
loop = loop.next;
} while ( loop != he );
recomputeNormal();
}
public Face(List<Vertex> vertexList, int[] faceVertices)
{
}
public void recomputeNormal() {
Point3d p0 = he.head.p;
Point3d p1 = he.next.head.p;
Point3d p2 = he.next.next.head.p;
Vector3d v1 = new Vector3d();
Vector3d v2 = new Vector3d();
v1.sub(p1,p0);
v2.sub(p2,p1);
n.cross( v1,v2 );
// TODO: compute the plane and matrix K for the quadric error metric
}
}
很抱歉最后一个问题,我有点着急,希望有一个简单的解决方案。 https://stackoverflow.com/questions/8031446/java-arraylist-removeo-returns-false-but-still-decrements-size-of-arraylist
【问题讨论】:
-
那是相当多的代码。我知道你很着急。如果您能提供SSCCE,这将有助于我们更快地回答您的问题。
-
就在顶部。我之前很着急,这不是一段时间。
-
不想给你带来困难,但这不是 100% 独立的。
标签: java data-structures arraylist mesh