【发布时间】:2011-11-05 01:24:06
【问题描述】:
我一直在使用 JMS 和 ActiveMQ。一切都在创造奇迹。我没有使用spring,我也不会。
接口javax.jms.MessageListener只有一种方法onMessage。在实现中,有可能会引发异常。如果实际上引发了异常,那么我说该消息未正确处理,需要重新尝试。所以,我需要 ActiveMQ 等待一会儿,然后重试。即我需要抛出的异常来回滚 JMS 事务。
我怎样才能完成这样的行为?
也许 ActiveMQ 中有一些配置我找不到。
或者...也许可以取消向消费者注册MessageListeners 并自己使用消息,在一个循环中,例如:
while (true) {
// ... some administrative stuff like ...
session = connection.createSesstion(true, SESSION_TRANSACTED)
try {
Message m = receiver.receive(queue, 1000L);
theMessageListener.onMessage(m);
session.commit();
} catch (Exception e) {
session.rollback();
Thread.sleep(someTimeDefinedSomewhereElse);
}
// ... some more administrative stuff
}
在几个线程中,而不是注册监听器。
或者...我可以以某种方式装饰/AOP/字节操作MessageListeners 来自己做这件事。
你会走哪条路,为什么?
注意:我无法完全控制MessageListeners 代码。
编辑 概念验证测试:
@Test
@Ignore("Interactive test, just a proof of concept")
public void transaccionConListener() throws Exception {
final AtomicInteger atomicInteger = new AtomicInteger(0);
BrokerService brokerService = new BrokerService();
String bindAddress = "vm://localhost";
brokerService.addConnector(bindAddress);
brokerService.setPersistenceAdapter(new MemoryPersistenceAdapter());
brokerService.setUseJmx(false);
brokerService.start();
ActiveMQConnectionFactory activeMQConnectionFactory = new ActiveMQConnectionFactory(bindAddress);
RedeliveryPolicy redeliveryPolicy = new RedeliveryPolicy();
redeliveryPolicy.setInitialRedeliveryDelay(500);
redeliveryPolicy.setBackOffMultiplier(2);
redeliveryPolicy.setUseExponentialBackOff(true);
redeliveryPolicy.setMaximumRedeliveries(2);
activeMQConnectionFactory.setRedeliveryPolicy(redeliveryPolicy);
activeMQConnectionFactory.setUseRetroactiveConsumer(true);
activeMQConnectionFactory.setClientIDPrefix("ID");
PooledConnectionFactory pooledConnectionFactory = new PooledConnectionFactory(activeMQConnectionFactory);
pooledConnectionFactory.start();
Connection connection = pooledConnectionFactory.createConnection();
Session session = connection.createSession(false, Session.DUPS_OK_ACKNOWLEDGE);
Queue helloQueue = session.createQueue("Hello");
MessageConsumer consumer = session.createConsumer(helloQueue);
consumer.setMessageListener(new MessageListener() {
@Override
public void onMessage(Message message) {
TextMessage textMessage = (TextMessage) message;
try {
switch (atomicInteger.getAndIncrement()) {
case 0:
System.out.println("OK, first message received " + textMessage.getText());
message.acknowledge();
break;
case 1:
System.out.println("NOPE, second must be retried " + textMessage.getText());
throw new RuntimeException("I failed, aaaaah");
case 2:
System.out.println("OK, second message received " + textMessage.getText());
message.acknowledge();
}
} catch (JMSException e) {
e.printStackTrace(System.out);
}
}
});
connection.start();
{
// A client sends two messages...
Connection connection1 = pooledConnectionFactory.createConnection();
Session session1 = connection.createSession(false, Session.AUTO_ACKNOWLEDGE);
connection1.start();
MessageProducer producer = session1.createProducer(helloQueue);
producer.send(session1.createTextMessage("Hello World 1"));
producer.send(session1.createTextMessage("Hello World 2"));
producer.close();
session1.close();
connection1.stop();
connection1.close();
}
JOptionPane.showInputDialog("I will wait, you watch the log...");
consumer.close();
session.close();
connection.stop();
connection.close();
pooledConnectionFactory.stop();
brokerService.stop();
assertEquals(3, atomicInteger.get());
}
【问题讨论】:
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非常感谢whaley 和@Ammar 的回答。我都赞成,因为你们都指出我走上了正确的道路。但还没有选择正确的答案。因为需要更多的测试。
标签: java transactions jms messaging activemq