如何在循环中减去多个输入的数字？

Question

程序应该通过一个循环（最多 10 个数字）收集用户输入的数字，如果用户输入负数则中断。收集输入后，它应该计算和、差、积和商。我的问题是我不知道找到差异的正确方法，我知道这一点是因为计算器的答案与程序的不同。

#include <stdio.h>

int main() {
int i;
double number, sum = 0.0, difference = 0, product = 1, quotient = 1;

for (i = 1; i <= 10; ++i) {
  printf("Enter n%d: ", i);
  scanf("%lf", &number);

  // if the user enters a negative number, break the loop
  if (number < 0.0) {
     break;
  }

  sum += number; // sum = sum + number;
  difference = number;
  product *= number;
  quotient = number / quotient;
}

printf("Sum = %.2lf", sum);
printf("\nDifference = %.2lf", difference);
printf("\nProduct = %.2lf", product);
printf("\nQuotient = %.2lf", quotient);

return 0;
}

Answer 1

double sum=0, difference=0, product =1 , quotient=1;
for (i = 1; i <= 10; ++i) {
  printf("Enter n%d: ", i);
  scanf("%lf", &number);
  if(number<0){
    break;
  }
  sum += number;
  difference -= number;
  product *= number;
  quotient = number/quotient;
}

我假设你还没有数组知识。