在 python networkx 中绘制一维点阵图

Question

我想绘制一维格子图，但我面临以下问题：

NetworkXPointlessConcept：空图没有路径，因此没有平均最短路径长度 这段代码有什么问题？ 谢谢。

N = 1000
x = 0
for n in range(1, N, 10):
    lattice_1d_distance = list()
    d = 0
    lattice_1d = nx.grid_graph(range(1,n))
    
    d = nx.average_shortest_path_length(lattice_1d)
    lattice_1d_distance.append(d)
    x.append(n)
plt.plot(x, lattice_1d_distance)  
plt.show()

Answer 1

根据networkx文档nx.grid_graph，输入是nx.grid_graph的维度列表

示例

print(list(range(1,4)))
nx.draw(nx.grid_graph(list(range(1,4))) # this is a two dimensional graph, as there is only 3 entries AND ONE ENTRY = 1

[1, 2, 3]

print(list(range(1,5)))
nx.draw(nx.grid_graph([1,2,3,4])) # this is a 3 dimensional graph, as there is only 4 entries AND ONE ENTRY = 1

[1, 2, 3, 4]

因此，假设您想 1. 绘制 距离与网格图维数增量的关系，但 每个维的大小保持不变，或者您想要到 2. 绘制 网格图每个维度的距离与大小增量，但维度数是恒定的：

import networkx as nx
import matplotlib.pyplot as plt

N = 10
x = []
lattice_1d_distance = []
for n in range(1, 10):
    d = 0
    lattice_1d = nx.grid_graph([2]*n) # plotting incrementing number of dimensions, but each dimension have same length.
    d = nx.average_shortest_path_length(lattice_1d)
    lattice_1d_distance.append(d)
    x.append(n)
plt.plot(x, lattice_1d_distance)  
plt.show()

N = 10
x = []
lattice_1d_distance = []
for n in range(1, 10):
    d = 0
    lattice_1d = nx.grid_graph([n,n]) # plotting 2 dimensional graphs, but each graph have incrementing length for each dimension.
    d = nx.average_shortest_path_length(lattice_1d)
    lattice_1d_distance.append(d)
    x.append(n)
plt.plot(x, lattice_1d_distance)  
plt.show()

另外，你需要注意列表变量的声明。