给定X和Y的坐标，如何在python中绘制相邻的多边形？

Question

我不熟悉在 python 中绘制图像。感谢您帮助解决我的问题。我有一个列表，其中包含对象字典以及相邻多边形的 X 和 Y 坐标列表。我能够提取 X 和 Y 坐标，但是当我使用 Matplotlib 绘制点时，我没有得到正确的多边形形状。

import matplotlib.pyplot as plt

shapes = [{'shape_attributes': {'name': 'polygon', 'all_points_x': [35, 28, 27, 31, 40, 51, 62, 72, 74, 71, 65, 57, 41], 'all_points_y': [74, 55, 32, 16, 4, 6, 12, 35, 56, 74, 83, 86, 81]}, 'region_attributes': {}}, None, {'shape_attributes': {'name': 'polygon', 'all_points_x': [6, 16, 24, 44, 69, 77, 81, 82, 80, 76, 69, 62, 51, 26, 9, 7], 'all_points_y': [85, 77, 78, 83, 92, 100, 106, 115, 118, 120, 122, 125, 126, 112, 98, 92]}, 'region_attributes': {}}]

shapesCordinates = []
for shape in shapes:
    if shape is not None:
        x_cor = shape['shape_attributes']['all_points_x']
        y_cor = shape['shape_attributes']['all_points_y']
        for x, y in zip(x_cor, y_cor):
            shapesCordinates.append((x, y))
print(shapesCordinates)
shapesCordinates.append(shapesCordinates[0])
xs, ys = zip(*shapesCordinates)
plt.figure()
plt.plot(xs,ys) 
plt.show()

Answer 1

您可能想一一绘制多边形。 plt.plot 会将列表中的所有点连接到下一个，不留空隙。

import matplotlib.pyplot as plt

shapes = [{'shape_attributes': {'name': 'polygon', 'all_points_x': [35, 28, 27, 31, 40, 51, 62, 72, 74, 71, 65, 57, 41], 'all_points_y': [74, 55, 32, 16, 4, 6, 12, 35, 56, 74, 83, 86, 81]}, 'region_attributes': {}}, None, {'shape_attributes': {'name': 'polygon', 'all_points_x': [6, 16, 24, 44, 69, 77, 81, 82, 80, 76, 69, 62, 51, 26, 9, 7], 'all_points_y': [85, 77, 78, 83, 92, 100, 106, 115, 118, 120, 122, 125, 126, 112, 98, 92]}, 'region_attributes': {}}]
plt.figure()
for shape in shapes:
    if shape is not None:
        x_cor = shape['shape_attributes']['all_points_x']
        y_cor = shape['shape_attributes']['all_points_y']
        plt.plot(x_cor+x_cor[:1], y_cor+y_cor[:1])
plt.show()