在 C 代码中打印底部带有 * 的倒三角形

Question

抱歉，我再次需要帮助。我得到了一份作业，需要在屏幕上打印出来。但是，我必须满足各种要求。老实说，我真的卡住了，因为当我在网上查看时，我必须考虑空格，它并没有告诉我如何将三角形底部的小尖端编辑成另一个。这就是我所做的，但考虑到我必须做的案例数量，它真的很疯狂，我认为它不可行。请帮忙！非常感谢您。

1) 顶部基本长度必须是用户输入，最大数量为 79（基本长度=79）。

2) 三角形必须是对称的。

xxxxxxxxx
 xxxxxxx
  xxxxx
   xxx
    *

#include<stdio.h>

int main()
{
int i, space, base_length, star;
printf("Enter the base length:\n");
scanf("%d",&base_length);

if (base_length==15)
{
    printf("XXXXXXXXXXXXXXX\n");
    printf(" XXXXXXXXXXXXX\n");
    printf("  XXXXXXXXXXX\n");
    printf("   XXXXXXXXX\n");
    printf("    XXXXXXX\n");
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}
else if (base_length==13)
{
    printf(" XXXXXXXXXXXXX\n");
    printf("  XXXXXXXXXXX\n");
    printf("   XXXXXXXXX\n");
    printf("    XXXXXXX\n");
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}
else if (base_length==11)
{
    printf("  XXXXXXXXXXX\n");
    printf("   XXXXXXXXX\n");
    printf("    XXXXXXX\n");
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}

else if (base_length==9)
{
    printf("   XXXXXXXXX\n");
    printf("    XXXXXXX\n");
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}

else if (base_length==7)
{
    printf("    XXXXXXX\n");
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}

else if (base_length==5)
{
    printf("     XXXXX\n");
    printf("      XXX\n");
    printf("       *\n");
}

else if (base_length==3)
{
    printf("      XXX\n");
    printf("       *\n");
}

else if  (base_length==1)
{
    printf("       *\n");
}
else
{
    printf("The maximum base length permitted is 79 and has to be an odd number.\nPlease try again with a valid number.\nThank You!!!");
}

return;

}

Answer 1

注意模式，用迭代代替。

喜欢这个

#include <stdio.h>

int main(void){
    int i, base_length, space, x;
    int bias_space = 7, rows;
    const char *X79 = //Prepare in advance because the maximum length is fixed
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXXX"
        "XXXXXXXXX";

    printf("Enter the base length:\n");
    scanf("%d", &base_length);

    if(base_length < 1 || base_length > 79 || (base_length & 1) == 0){
        printf("The maximum base length permitted is 79 and has to be an odd number.\nPlease try again with a valid number.\nThank You!!!");
        return -1;
    }
    rows = base_length / 2;//Number of rows excluding the top
    bias_space -= rows;
    if(bias_space < 0) //When there are more than 7 lines, there is no bias space.
        bias_space = 0;

    for(i = rows, space = 0, x = base_length; i--; space++, x -= 2)
        printf("%*s%.*s\n", bias_space + space, "", x, X79);
    printf("%*s%c\n", bias_space + space, "", '*');
}

Answer 2

您可以使用带有帮助函数的简单递归函数：

#include <stdio.h>

void triangle(int size);
void triangle_aux(int size, int n);

int main()
{
    int base_length;

    printf("Enter the base length:\n");
    scanf("%d",&base_length);

    if(base_length < 1 || base_length > 79 || base_length%2 == 0)
        printf("The maximum base length permitted is 79 and has to be an odd number.\nPlease try again with a valid number.\nThank You!!!");
    else
        triangle(base_length);
}

void triangle(int size) {
    triangle_aux(size, 0);
}

void triangle_aux(int size, int n)
{
    int i;
    for(i=0; i<n; i++)
        printf(" ");
    if(n==size/2)
        printf("*\n");
    else {
         for(i=n; i<size-n; i++)
              printf("X");
         printf("\n");
         triangle_aux(size, n+1);
    }
}