我在 C 中对这个数组做错了什么？

Question

我需要知道“Maria”在这个数组中出现了多少次，但是当我运行它时，它说它出现了 51 次，我认为它只有 8 次

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
    int g;
    int i;
    const char * nombres[40] = {"Sandra Marisol","Juan Luis","Perez Luis","Carlitos","Maria","Mariana", "Carlota","Anthony",
                        "Fernando Jan","Alfonso Roche","Julieta Zacatenco","Maria de los Angeles","Laura Jessica",
                        "Andrea Maria","Jose Maria","Andres Molina","Aline Derrant","Paquito","Luisa","Ana Maria",
                        "Caleb","Luis Fernando","Mario Alberto","Paula Monica","Otoniel","Elias Primero","Maurico Enrique",
                        "Anastasia Maria","Maria Juana","Juana de Arco","Aria Montgomery""Hanna Maria","Magdalena","David Green",
                        "Florian Drake","Edward Jones","Joakin Broder","Paar","Alicia Torres","Juan Pablo"};
    for(i = 0; i>40; i++)
    {
        printf("%s\n", nombres[40]);
        if(nombres[i] == "Maria")
        g++;
    }
    if(g>0){
            printf("El nombre de Maria aparece %d veces.", g);
        }
        else {
            printf("El nombre de Maria NO aparece");
        }

    system("pause");
    return 0;

}

Answer 1

if(nombres[i] == "Maria")

你不能像这样比较字符串。您需要使用strstr() 在字符串中查找子字符串。

另外， printf("%s\n", nombres[40]); 可能应该有 i 而不是 40。而你在上面的 for 循环中间的比较是倒退的。

而且...可能还有其他错误，但这对我来说已经足够了。

Answer 2

有很多错误.....让我们看看我能解决多少..xd

 #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>

    int main(int argc, char *argv[])
    {
        int g=0;
        int i;
        const char * nombres[40] = {"Sandra Marisol","Juan Luis","Perez Luis","Carlitos","Maria","Mariana", "Carlota","Anthony",
                            "Fernando Jan","Alfonso Roche","Julieta Zacatenco","Maria de los Angeles","Laura Jessica",
                            "Andrea Maria","Jose Maria","Andres Molina","Aline Derrant","Paquito","Luisa","Ana Maria",
                            "Caleb","Luis Fernando","Mario Alberto","Paula Monica","Otoniel","Elias Primero","Maurico Enrique",
                            "Anastasia Maria","Maria Juana","Juana de Arco","Aria Montgomery""Hanna Maria","Magdalena","David Green",
                            "Florian Drake","Edward Jones","Joakin Broder","Paar","Alicia Torres","Juan Pablo"};
        for(i = 0; i<40; i++)
        {
            printf("%s\n", nombres[i]);
            if(!strcmp(nombres[i],"Maria"))
            g++;
        }
        if(g>0){
                printf("El nombre de Maria aparece %d veces.", g);
            }
            else {
                printf("El nombre de Maria NO aparece");
            }

        return 0;

    }

这里的计数器变量 g 没有被初始化。它应该初始化为 0，否则它包含一些垃圾值。然后在 for 循环中条件错误，循环没有被执行，因为你在这里写 I>40，我被初始化为 0，所以条件为假并且循环不运行。然后循环中的 printf 包含 nombres[40] ，它给出了一个空指针，因为你的姓氏是 hombres[39]。然后在 if 条件下，你不能像其他变量一样只比较字符串，你必须使用 lib 函数，它是 strcmp 表示字符串比较。 在以下情况下

strcmp(s1,s2);

**

*if s1==s2 then it returns 0.
If s1>s2 then it returns 1
If s1<s2 it returns -1 

---

所以我写了!strcmp(); 所以如果字符串匹配，它将返回 0 和 '!'将其转换为 1。 希望这可行。荣誉。