通过 PHP 使用 POST 或 GET 传递数组变量

Question

我需要一些帮助来尝试序列化 html 中的隐藏元素，而不是通过 post 将值传递给 php。这是我的代码：

<form action = "index.php" method = "POST" >
Enter name: <input type ="text" name = "name"><br></br>
enter ID: <input type = "text" name = "id"><br></br>
<input type = "hidden"
id = "hiddenStrArr"
name "hiddenStrArr"
value = "<?php print base64_encode(serialize("$arrayVar"))?>">
<input type = "submit" name = "submitButton" value = "Submit">
</form>

<?php
$nameExists = FALSE;
$name = ($_POST['name']);
$id = ($_POST['id']);
$hiddenStrArr = $_POST["hiddenStrArr"];
$arrayVar = unserialize(base64_decode($hiddenArray));

我的 php 中有一个 foreach 循环中的数组，它将检查来自用户的输入以及我的数组中的数据。问题是我的数组保持不变。如果我再次发布，它将重新从旧数组开始，但我希望它能够随着用户输入而更新。我正在尝试遵循本指南Passing Array Variables using POST or GET with PHP，但我不太了解。有人请帮助我或解释这是如何工作的。我收到一条错误消息，说 $name $id $hiddenStrArr 和 $arrayVar 是未定义的索引。谢谢你。

这里有更多代码可以帮助解释发生了什么：

 <?php
    $myTwoDimArr = array(1 =>  array("name1", 0, "123"),
    2 => array("name2", 123, "456"),
    3 =>  array("name3", 456, "789"),
    4 =>  array("name3", 789, "101112"));
    ?>

    <form action = "index.php" method = "POST" >
    Enter name: <input type ="text" name = "name"><br></br>
    enter ID: <input type = "text" name = "id"><br></br>

<input type = "hidden"
id = "hiddenStrArr"
name "hiddenStrArr"
value = "<?php print base64_encode(serialize("$arrayVar"))?>">
<input type = "submit" name = "submitButton" value = "Submit">
</form>

    <?php
    $nameExists = FALSE;
    $name = ($_POST['name']);
    $id = ($_POST['id']);
    $hiddenStrArr = $_POST["hiddenStrArr"];
    $arrayVar = unserialize(base64_decode($hiddenArray));
    //this will check values from the html form against
    //the values stored in the array than add 5 to $value[1]
    foreach($myTwoDimArr as $key => $value){
        if($key == $id && $value[0] == $name){
        $myTwoDimArr[$key][1] = $myTwoDimArr[$key][1] + 5;
        $nameExists = TRUE;
        }
    }               //if values don't exist this creates a new element
                    //in the declared array
                    if ($nameExists === FALSE){
                        $newData = array($name, 1, date("Y-m-d"));
                        $myTwoDimArr[$id] = $newData;
                    }
    //this will print values from the array
    //the values are not being saved, I was hoping to use
    //hidden element to accomplish this so that user may input
    //more new values or add to existing values
    foreach($myTwoDimArr as $key => $value){
                        echo "<tr><td>".$key."</td>
                                    <td>".htmlspecialchars($value[0])."</td>
                                    <td>".htmlspecialchars($value[1])."</td>
                                    <td>".htmlspecialchars($value[2])."</td></tr>";
                    }

    ?>

Answer 1

您的变量在您呈现表单的下方定义。这就是为什么您会收到未定义的错误。那个时候变量不存在。

在这种情况下你应该做的，我几乎在任何情况下都建议你在最后输出你的 html。因此在渲染之前计算。

<?php
    $nameExists = FALSE;
    $name = isset($_POST['name']) ? $_POST['name'] : '';
    $id = isset($_POST['id']) ? $_POST['id'] : '';
    $hiddenStrArr = isset($_POST['hiddenStrArr']) ? $_POST['hiddenStrArr'] : '';
    $arrayVar = unserialize(base64_decode($hiddenStrArr));
?>

<form action = "index.php" method = "POST" >
    Enter name: <input type ="text" name = "name"><br></br>
    enter ID: <input type = "text" name = "id"><br></br>
    <input type = "hidden"
    id = "hiddenStrArr"
    name "hiddenStrArr"
    value = "<?php print base64_encode(serialize("$arrayVar"))?>">
    <input type = "submit" name = "submitButton" value = "Submit">
</form>