【发布时间】:2018-10-19 10:11:11
【问题描述】:
我正在尝试实现以前在 Excel 中完成的功能,但找不到实现它的方法。
我有两个数据集:一个是我的基本数据集,另一个是查找表。 我的基地有两列,人的名字和姓氏。我的查找表也有前两列,但它还包括一个替换名字。
People <- data.frame(
Fname = c("Tom","Tom","Jerry","Ben","Rod","John","Perry","Rod"),
Sname = c("Harper","Kingston","Ribery","Ghazali","Baker","Falcon","Jefferson","Lombardy")
)
Lookup <- data.frame(
Fname = c("Tom","Tom","Rod","Rod"),
Sname = c("Harper","Kingston","Baker","Lombardy"),
NewFname = c("Tommy","Tim","Roderick","Robert")
)
我想要做的是用 NewFname 替换 Fname,这取决于两个条件:两个数据帧中的 Fname 和 Sname 匹配。这是因为我有一个数据集,其中包含需要处理的其他 40,000 行数据。最终,我希望最终得到以下数据框:
People <- data.frame(
Fname = c("Tommy","Tim","Jerry","Ben","Roderick","John","Perry","Robert"),
Sname = c("Harper","Kingston","Ribery","Ghazali","Baker","Falcon","Jefferson","Lombardy")
)
但是,我想要一个函数解决方案,这样我就不必单独手动输入条件和替换名称。到目前为止,我有以下(有问题的)解决方案,这将涉及在 dplyr 中使用 mutate 生成一个新列,但它不起作用
People %>%
mutate(NewName = if_else(
Fname == Lookup$Fname & Sname == Lookup$Sname, NewFname, Fname
))
【问题讨论】:
-
merge(People, Lookup, all.x = TRUE)
标签: r dplyr str-replace