SharedPreferences 不断获得默认值答案

【问题标题】：SharedPreferences keep getting default valueSharedPreferences 不断获得默认值
【发布时间】：2012-10-31 12:28:09
【问题描述】：

我一直在获取默认值，或者我的 UI 将显示 null，或者如果我使用整数，它也会显示该默认值，这里它是字符串形式，请帮助

//putting the information in shared preferences
TextView pScore1=(TextView)findViewById(R.id.pScore1f);


SharedPreferences peepsScores2= PreferenceManager.getDefaultSharedPreferences(GamePlayFirst.this);
SharedPreferences.Editor editor2 =peepsScores2.edit();
String userScore11 = pScore1.getText().toString();
  editor2.putString("userScore11",userScore11);
  editor2.commit();

  //getting it and editing it

  SharedPreferences peepsScores2 = PreferenceManager.getDefaultSharedPreferences(this);
    int u;
    int one =1;
    int newUsrScore1=1;
    String userScore11 = peepsScores2.getString("userScore11",null);
    u=Integer.parseInt(userScore11);
        newUsrScore1 = u+one;
        String newUserScore1  = Integer.toString(newUsrScore1);

    SharedPreferences.Editor editor = peepsScores2.edit();
    editor.putString(newUserScore1, NewUserScore1);
      editor.commit();

    //getting it and displaying it on the UI

    SharedPreferences peepsScores2 = PreferenceManager.getDefaultSharedPreferences(this);
    String userScore11 = peepsScores2.getString("NewuserScore1",null);


  pScore1.setText(" "+userScore11);

【问题讨论】：

尝试查看xml，看看commit是否成功。
你没有在编辑后调用提交..

标签： android sharedpreferences

【解决方案1】：

我已为您的代码添加了一些注释，请检查：

//putting the information in shared preferences
TextView pScore1=(TextView)findViewById(R.id.pScore1f);


SharedPreferences peepsScores2= 

PreferenceManager.getDefaultSharedPreferences(GamePlayFirst.this);
SharedPreferences.Editor editor2 =peepsScores2.edit();
String userScore11 = pScore1.getText().toString();
  editor2.putString("userScore11",userScore11);
  editor2.commit();

  //getting it and editing it

  SharedPreferences peepsScores2 = PreferenceManager.getDefaultSharedPreferences(this);
    int u;
    int one =1;
    int newUsrScore1=1;
    String userScore11 = peepsScores2.getString("userScore11",null);
    u=Integer.parseInt(userScore11);
        newUsrScore1 = u+one;
        String newUserScore1  = Integer.toString(newUsrScore1);

    SharedPreferences.Editor editor = peepsScores2.edit();

     //@Praful: here newUserScore1 seems to be integer value and you are storing 
    //null here. I think it it should be 
    //`editor.putString("NewuserScore1", newUsrScore1);`
    editor.putString(newUserScore1, null);

     //@Praful: call commit here
    editor.commit;

    //getting it and displaying it on the UI

    SharedPreferences peepsScores2 = PreferenceManager.getDefaultSharedPreferences(this);
    String userScore11 = peepsScores2.getString("NewuserScore1",null);


  pScore1.setText(" "+userScore11);

【讨论】：

这个答案也解决了我的类似问题，我忘记输入 editor.commit();添加后它起作用了！ :) 谢谢

【解决方案2】：

这一行

editor.putString(newUserScore1, null);

应该是

editor.putString("NewuserScore1",newUserScore1);

并且不要忘记使用editor.commit();提交您的更改

【讨论】：

capitol N 哈哈，我是有史以来最糟糕的打字员
很高兴我能帮上忙。祝你好运！

【解决方案3】：

当您使用 SharedPreference 时，永远不要忘记致电 commit() 以保存您的更改。

    SharedPreferences.Editor editor = peepsScores2.edit();
    editor.putString("NewuserScore1", newUserScore1);
    editor.commit();

【讨论】：