【发布时间】:2015-05-14 12:42:11
【问题描述】:
我创建了两个字符串变量,“questionString”和“answerSetId”——我已将第一个变量分配给一个 textview——我想将第二个变量传递给我的 db helper 类:
public void showNextRandomQuestion3() {
SQLDatabaseHelper db = new SQLDatabaseHelper(this);
//get the data from the database
List<List<String>> listList = db.getAllAnswersByQuestion1();
//Get the question/text/answer Strings
List<String> questionStrings = listList.get(0); //question Strings
List<String> answerSetIds = listList.get(4);
//Generate random index
Random r = new Random();
int rand = Math.abs((r.nextInt() % questionStrings.size()));
//get answer description for randomly selected question
String questionString = questionStrings.get(rand);
String answerSetId = answerSetIds.get(rand);
questionView.setText(questionString);
}
在我的数据库助手类中,我想使用这个字符串变量作为我的查询:
public List<List<String>> getAnswers() {
List<String> array1 = new ArrayList<String>();
List<String> array2 = new ArrayList<String>();
SQLiteDatabase db = this.getReadableDatabase();
String selectQuery = "SELECT * FROM " + TABLE_ANSWERS + "WHERE " + ASID
+ " = " + ??answerSetId??;
Cursor c = db.rawQuery(selectQuery, null);
if (c.moveToFirst()) {
do {
String textdescr = c.getString(c.getColumnIndex(TDESCR));
String answersdescr = c.getString(c.getColumnIndex(ADESCR));
array1.add(textdescr);
array2.add(answersdescr);;
} while (c.moveToNext());
}
List< List<String> > listArray2 = new ArrayList< List<String> >();
listArray2.add(array1);
listArray2.add(array2);
return listArray2;
}
实现这一目标的最佳方法是什么?
【问题讨论】:
标签: android arrays android-intent get