如何从列表中返回图表？

Question

此函数tickets_ages() 计算每个年龄组购买的活动门票数量。

我需要创建一个可视化表示来显示每个年龄段的门票销售情况，但我不知道该怎么做。我已经完成了基本功能，该函数只输出每个年龄段+售出的门票数量。

计算：函数取最大数，在本例中为 18，然后除以 4，即 4.5。 4.5 将代表图表上的一个刻度线*

对于其余数字，每个数字除以 4.5，与最大除法因子 18 相同。

0 to 20: 12 ---> becomes 2.66
20 to 40: 15 ---> becomes 3.33
40 to 60: 16 ---> becomes 3.55
60 to 80: 15 ---> becomes 3.33
80 and over: 18 ---> 4.5

这是我的代码：

def sort_list(value):
    sorted_v = list(set(value)) #This just puts the values once so they dont repeat, dont worry about it
    sorted_v.sort()
    return sorted_v


'''
The list
'''
ages = ['0 to 20', '0 to 20', '0 to 20', '0 to 20','0 to 20', '0 to 20', '0 to 20', '0 to 20','0 to 20', '0 to 20', '0 to 20', '0 to 20', '20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','20 to 40','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','40 to 60','60 to 80','60 to 80','60 to 80','60 to 80','60 to 80','60 to 80', '40 to 60','60 to 80','60 to 80', '80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','80 and over','40 to 60','60 to 80','60 to 80','60 to 80','60 to 80','60 to 80','60 to 80', '40 to 60','60 to 80','80 and over'] 

'''
Main function
'''
def tickets_ages(ages):
    sort_thelist = sort_list(ages)
    string_s = ''
    for source in sort_thelist:
        output = ages.count(source)        
        string_s += '{}: {} \n'.format(source, output)
    return string_s    

'''
Test code
'''

print(tickets_ages(ages))

输出应该是：

0 to 20: ***  #---> 2.66
20 to 40: *** #---> 3.33
40 to 60: *** #---> 3.55
60 to 80: *** #---> 3.33
80 and over: ***** #---> 4.5

Answer 1

根据经验，如果您打算进一步处理函数，请不要从函数返回格式化输出。修改您的函数以返回原始结果：

def tickets_ages(ages):
    sort_thelist = sort_list(ages)
    output = []
    for source in sort_thelist:
        output.append((source, ages.count(source)))
    return output

然后处理输出以计算“tick”值（即您的示例中的 4.5）：

results = tickets_ages(ages)
tickets = list(zip(*results))[1]
tick = max(tickets) / 4

您现在可以使用以下信息打印结果：

for age, ticket in results:
    score = round(ticket / tick, 2)
    stars = '*' * round(score)
    print(f"{age}: {score}: {stars}")
print()

这应该打印出来：

0 to 20: 2.67: ***
20 to 40: 3.33: ***
40 to 60: 3.56: ****
60 to 80: 3.33: ***
80 and over: 4.0: ****

score 值用于演示目的，如果不需要，可以将其从 f 字符串中删除。

编辑：如果您想修改原始函数以返回图表：

def tickets_ages(ages):
    sort_thelist = sort_list(ages)
    results = []
    output = ""
    for source in sort_thelist:
        results.append((source, ages.count(source)))
    tickets = list(zip(*results))[1]
    tick = max(tickets) / 4
    for age, ticket in results:
        score = round(ticket / tick, 2)
        stars = '*' * round(score)
        output += f"{age}: {score}: {stars}\n"
    return output

print(tickets_ages(ages))