【发布时间】:2014-03-20 15:23:23
【问题描述】:
我有一个循环,它给出给定开始时间和结束时间之间半小时数的结果
$start = new DateTime('09:00:00');
// add 1 second because last one is not included in the loop
$end = new DateTime('16:00:01');
$interval = new DateInterval('PT30M');
$period = new DatePeriod($start, $interval, $end);
$previous = '';
foreach ($period as $dt) {
$current = $dt->format("h:ia");
if (!empty($previous)) {
echo "<input name='time' type='radio' value='{$previous}|{$current}'>
{$previous}-{$current}<br/>";
}
$previous = $current;
}
上述循环的结果如下
09:00am-09:30am
09:30am-10:00am
10:00am-10:30am
10:30am-11:00am
11:00am-11:30am
11:30am-12:00pm
12:00pm-12:30pm
12:30pm-01:00pm
01:00pm-01:30pm
01:30pm-02:00pm
02:00pm-02:30pm
02:30pm-03:00pm
03:00pm-03:30pm
03:30pm-04:00pm
我想要实现的是排除下面提到的一些时间,如果它存在于另一个数组$existing_time 中,看起来像这样
[0] => Array
(
[start_time] => 2014-03-28T14:00:00+1100
[end_time] => 2014-03-28T14:30:00+1100
)
[1] => Array
(
[start_time] => 2014-03-28T15:00:00+1100
[end_time] => 2014-03-28T15:30:00+1100
)
)
我需要有关如何执行此操作的帮助,任何帮助将不胜感激
【问题讨论】:
标签: php arrays datetime for-loop