1)我们需要一些逻辑(函数)来获取每个对象的“比较值”。例如,给定对象a: { boxTop: 320, boxLeft: 1750, boxHeigth: 245, boxWidth: 310 },作为输入,我们希望值(字符串)'{"boxTop":320,"boxLeft":1750}' 作为输出,然后我们可以使用该字符串与其他值进行比较。
2) 给定一个值,例如字符串'{"boxTop":320,"boxLeft":1750}',我们需要一些逻辑来计算该值在某个集合中出现的次数(例如列表、字典)。有很多方法可以解决这个问题,我决定使用一个字典,其中 key 代表某个值,字典的 value 代表该键在集合中出现的次数。
这是一个 JavaScript(节点)实现,因为您的名字中有 javascript:
const objectsData = {
a: { boxTop: 320, boxLeft: 1750, boxHeigth: 245, boxWidth: 310 },
b: { boxTop: 20, boxLeft: 580, boxHeigth: 245, boxWidth: 310 },
c: { boxTop: 320, boxLeft: 1750, boxHeigth: 245, boxWidth: 310 },
d: { boxTop: 320, boxLeft: 1750, boxHeigth: 245, boxWidth: 310 },
e: { boxTop: 136, boxLeft: 10, boxHeigth: 245, boxWidth: 310 },
};
function getBoxLeftAndBoxTop(obj) {
const { boxTop, boxLeft } = obj;
return JSON.stringify({ boxTop, boxLeft });
}
const counterBoxLeftAndBoxTop = {};
for (const key of Object.keys(objectsData)) {
const box = getBoxLeftAndBoxTop(objectsData[key]);
const currentCount = counterBoxLeftAndBoxTop[box];
counterBoxLeftAndBoxTop[box] = currentCount ? currentCount + 1 : 1;
}
console.log(counterBoxLeftAndBoxTop);
/* Outputs:
{
'{"boxTop":320,"boxLeft":1750}': 3,
'{"boxTop":20,"boxLeft":580}': 1,
'{"boxTop":136,"boxLeft":10}': 1
}
*/
console.log(`Objects that appears 2 or more times: `);
for (const key of Object.keys(objectsData)) {
const box = getBoxLeftAndBoxTop(objectsData[key]);
const currentCount = counterBoxLeftAndBoxTop[box];
if (currentCount >= 2) {
console.log(key);
}
}
/* Outputs:
Objects that appears 2 or more times:
a
c
d
*/