以特定方式在php数组中显示来自mysql的坐标答案

【问题标题】：Displaying coordinates from mysql in a php array in specific way以特定方式在php数组中显示来自mysql的坐标
【发布时间】：2020-04-27 20:24:03
【问题描述】：

我要做的是从 MySQL 表中获取 lat 和 lon 列，并将其放入具有这种格式“lat lon”的数组中。这是我到目前为止所做的：

<?php
    $connection = mysqli_connect("localhost", "root", "", "whichever");
    $sql = "SELECT lat, lon FROM whatever";
    $result = mysqli_query($connection, $sql);
    $latlon = array();
    $index = 0;
    while($row = mysqli_fetch_assoc($result)){ 
     $latlon[$index] = $row;
     $index++;
    }
    $points = $latlon // consider that this was initially stated as $points= array("lat lon", "lat lon", ..."lat lon")
?>

但它只是以这种方式给了我数组：

Array ( [0] => Array ( [lat] => 37.9661239 [lon] => 23.7528766 ) [1] => Array ( [lat] => 37.9661321 [lon] => 23.7528387 )

当我使用print_r($points)时。

任何帮助将不胜感激。

【问题讨论】：

结果应该是什么样子？
SELECT CONCAT(lat, ' ', lon) AS latlon FROM whatever

标签： php mysql arrays

【解决方案1】：

while($row = mysqli_fetch_assoc($result)){ 
     $latlon[$index] = $row['lat'] . ' ' . $row['lon'];
     $index++;
}

【讨论】：

【解决方案2】：

试试这个：

<?php
    $connection = mysqli_connect("localhost", "root", "", "whichever");
    $sql = "SELECT lat, lon FROM whatever";
    $result = mysqli_query($connection, $sql);
    $latlon = array();
    $index = 0;
    while($row = mysqli_fetch_assoc($result)){
    $lat = $row['lat'];
    $lon = $row['lon'];
    $latlon[$index] = $lat . ' ' . $lon;
    $index++;
    }
    $points = $latlon // consider that this was initially stated as $points= array("lat lon", "lat lon", ..."lat lon")
?>

【讨论】：