【发布时间】:2016-09-22 23:34:32
【问题描述】:
我无法超越下图所示的点。
我得到:
Cannot convert value of type 'Element' to expected argument type 'IntegerLiteralType' (aka 'Int')
在我将数据从“元素”移动到“T”的那一行。另外,我还没有弄清楚如何将截断扩展到 UInt。
我们将不胜感激。
protocol Truncating {
init(truncatingBitPattern: IntegerLiteralType)
}
extension Int {
init(truncatingBitPattern value: Int) { self.init(truncatingBitPattern: value.toIntMax()) }
}
protocol Bitshiftable {
func <<(lhs: Self, rhs: Self) -> Self
func >>(lhs: Self, rhs: Self) -> Self
func <<=(inout lhs: Self, rhs: Self)
func >>=(inout lhs: Self, rhs: Self)
}
protocol ArrayConvertable: IntegerType, Bitshiftable, Truncating {}
extension Int : ArrayConvertable {}
extension Int8 : ArrayConvertable {}
extension Int16 : ArrayConvertable {}
extension Int32 : ArrayConvertable {}
extension Int64 : ArrayConvertable {}
//extension UInt : ArrayConvertable {}
extension UInt8 : ArrayConvertable {}
extension UInt16 : ArrayConvertable {}
extension UInt32 : ArrayConvertable {}
extension UInt64 : ArrayConvertable {}
extension Array where Element: ArrayConvertable {
func toInt<T: ArrayConvertable>() -> T?
{
let targetSize = sizeof(T)
let sourceSize = sizeof(Element)
let sourceByteCount = count * sourceSize
guard targetSize == sourceByteCount else { return nil }
var n: T = 0
for e in self {
var dataChunk = e
for i in 0..<sourceSize {
n = n | T(truncatingBitPattern: dataChunk)
if i + 1 < sourceSize {
n = n << 8
dataChunk = dataChunk >> 8
}
}
}
return n
}
}
func test() {
let a8: [UInt8] = [0xab, 0xba, 0xda, 0xba, 0xd0, 0xd1, 0xd2, 0xd3, 0xfe, 0xdc, 0xba, 0x98, 0x76, 0x54, 0x32, 0x10]
let a16: [UInt16] = [0xabba, 0xdaba, 0xd0d1, 0xd2d3, 0xfedc, 0xba98, 0x7654, 0x3210]
let a32: [UInt32] = [0xabbadaba, 0xd0d1d2d3, 0xfedcba98, 0x76543210]
let a64: [UInt64] = [0xabbadabad0d1d2d3, 0xfedcba9876543210]
var n8: UInt8 = 0
var n16: UInt16 = 0
var n32: UInt32 = 0
var n64: UInt64 = 0
print("--- 08 bit source")
n8 = a8.toInt()!
n16 = a8.toInt()!
n32 = a8.toInt()!
n64 = a8.toInt()!
print(n8, n16, n32, n64)
print("--- 16 bit source")
n8 = a16.toInt()!
n16 = a16.toInt()!
n32 = a16.toInt()!
n64 = a16.toInt()!
print(n8, n16, n32, n64)
print("--- 32 bit source")
n8 = a32.toInt()!
n16 = a32.toInt()!
n32 = a32.toInt()!
n64 = a32.toInt()!
print(n8, n16, n32, n64)
print("--- 64 bit source")
n8 = a64.toInt()!
n16 = a64.toInt()!
n32 = a64.toInt()!
n64 = a64.toInt()!
print(n8, n16, n32, n64)
}
test()
【问题讨论】:
-
无论实现如何:您的断言
targetSize == sourceByteCount在示例中总是会失败,因为输入数组对于单个 8/16/32/64 位整数来说太大了。或者结果应该是目标类型的array? -
如果输入为
let a32: [UInt32] = [0x01020304, 0x05060708, 0x090a0b0c, 0x0d0e0f10],目标类型为UInt16,预期的结果是什么?对于目标类型UInt64? -
@MartinR body 有一些错误,但是 targetSize == sourceByteCount 如果,例如,目标是 UInt16,源是 [UInt8].count == 2。这个函数的结果总是整数之一。
-
@MartinR 您的示例的结果最好是 0x0304。
-
我正在研究的一个可能方向是将 truncatingBitPattern 推广到所有整数。