如何折叠一组关键过滤对象？

Question

假设我正在从节点存储库中获取一组对象，例如：

const array = [
  {
    id: 1,
    title: "SNKEP1",
    ep: 1,
    season: 1
  },
  {
    id: 2,
    title: "SNKEP2",
    ep: 2,
    season: 1
  },
  {
    id: 3,
    title: "SNKEP3",
    ep: 3,
    season: 1
  },
  {
    id: 4,
    title: "SNKEP1",
    ep: 1,
    season: 2
  },
  {
    id: 5,
    title: "SNKEP2",
    ep: 2,
    season: 2
  },
  {
    id: 6,
    title: "SNKEP3",
    ep: 3,
    season: 2
  },
  {
    id: 7,
    title: "SNKEP1",
    ep: 1,
    season: 3
  },
  {
    id: 8,
    title: "SNKEP2",
    ep: 2,
    season: 3
  },
  {
    id: 9,
    title: "SNKEP3",
    ep: 3,
    season: 3
  }
];

我想得到这样的结果：

const filteredEps = [
  {
    season: 1,
    ep: [{/* filtered eps */}]
  },
  {
    season: 2,
    ep: [{/* filtered eps */}]
  },
  {
    season: 3,
    ep: [{/* filtered eps */}]
  },
];

我如何得到这个结果？

Answer 1

你可以这样做：

let filteredEps = [];
for (const value of array) {
    let [eps] = filteredEps.filter((_eps) => _eps.season === value.season);
    if (eps) {
        eps.ep.push(value.ep);
    } else {
        filteredEps.push({season: value.season, ep: [value.ep]});
    }
}