在php中从数组创建字符串

Question

我有这个对象

[{"name":"Fressnapf","isChecked":true},{"name":"Whiskas","isChecked":true},{"name":"Purina","isChecked":true}]

我想构建一个这样的字符串：

"Fressnapf","Whiskas","Purina"

但如果 isChecked 布尔值之一是（例如这样的 false：[{"name":"Fressnapf","isChecked":true},{"name":"Whiskas","isChecked":false},{"name":"Purina","isChecked":true}]）

那么字符串应该是这样的：

"Fressnapf","普瑞纳"

所以我有一个$brands 对象（上面的 json 形式），现在呢？

Answer 1

// Decode json to PHP array  json_decode(<JSON>, true) the second parameter converts to array instead of object
$arrays = json_decode('[{"name":"Fressnapf","isChecked":true},{"name":"Whiskas","isChecked":true},{"name":"Purina","isChecked":true}]', true);

// Create an array to store the output data you want
$checked_names = [];

// Loop through the arrays of properties in your JSON to find out if the value isChecked is true and if so add the name to your checked_names array
foreach ($arrays as $array) {
  if (!empty($array['isChecked'])) {
    $checked_names[] = $array['name'];    
  }
}

// Output with surrounding quotation marks.... implode will turn your array into a string with "glue" -- stuff in between the items... so you need the extra quotes on the outside as well
echo '"' . implode('", "', $checked_names) . '"';

Answer 2

  // --- Decode the json array.

    $array = json_decode('[{"name":"Fressnapf","isChecked":false},{"name":"Whiskas","isChecked":true},{"name":"Purina","isChecked":true}]');

    $string = array();

    // ---  Loop through the array. 
    foreach($array as $item){

        // --- Check to see if item is checked. If it is, stick it into array $string.
        if($item->isChecked != false){
            $string[] = $item->name;
        }
    }

    // --- Transform $string to an actual string.
    $string = implode(', ', $string);

    echo $string;