【发布时间】：2018-05-01 17:58:02
【问题描述】：
我有一个需要排序的对象数组。如果对象具有“search-filter-type”类，则需要按特定顺序排序（参见：car_types_order）。对于数组中的所有其他对象，它应该按标签的字母顺序排序。我下面的作品，我想知道是否应该有两个单独的排序功能，或者是否有更清洁的方法来实现这一点？谢谢！
代码：
var car_types_order = ['Small Cars', 'Medium Cars', 'Large Cars', 'SUVs & Crossovers', 'Vans', 'Luxury',
'Convertibles', 'Sports', 'Wagons', 'Hybrids', 'Electric', 'Pickup Trucks', 'Off-Road Vehicles', 'RVs',
'Commercial', 'Specialty'];
filters.sort(function(a, b){
if (a.class == "search-filter-type" || b.class == "search-filter-type")
return car_types_order.indexOf(a.label) - car_types_order.indexOf(b.label);
else
{
if (a.label < b.label)
return -1;
if (a.label > b.label)
return 1;
}
return 0;
});
示例对象：
{title: "Rental Company", class: "search-filter-company", label: "Hertz", id: "filter-companies-HZ", value: "HZ"}
{title: "Rental Company", class: "search-filter-company", label: "Silvercar", id: "filter-companies-SC", value: "SC"}
{title: "Rental Company", class: "search-filter-company", label: "NextCar", id: "filter-companies-NC", value: "NC"}
{title: "Rental Company", class: "search-filter-company", label: "National", id: "filter-companies-NA", value: "NA"}
{title: "Rental Company", class: "search-filter-company", label: "Payless", id: "filter-companies-ZA", value: "ZA"}
{title: "Rental Company", class: "search-filter-company", label: "Sixt", id: "filter-companies-SX", value: "SX"}
{title: "Rental Company", class: "search-filter-company", label: "Thrifty", id: "filter-companies-ZT", value: "ZT"}
{title: "Car Type", class: "search-filter-type", label: "Commercial", id: "filter-types-commercial", value: "SKAR"}
{title: "Rental Company", class: "search-filter-company", label: "Routes", id: "filter-companies-RO", value: "RO"}
{title: "Car Type", class: "search-filter-type", label: "Electric", id: "filter-types-electric", value: "ICAE"}
{title: "Car Type", class: "search-filter-type", label: "Medium Cars", id: "filter-types-medium", value: "FCAR"}
{title: "Car Type", class: "search-filter-type", label: "Small Cars", id: "filter-types-small", value: "CCAR"}
【问题讨论】：
-
由于您正在执行自定义排序，IMO，我认为您所拥有的一切都很好。您可以将两种排序方式分解为函数，然后它可以重用，这可能是改进设计的一种方式。但是排序本身，仍然需要实现你所拥有的逻辑。
-
您要按字母顺序排列在底部还是顶部？
-
不一定需要
class订购。标签本身需要排序（对于搜索过滤器类型），它应该遵循 car_types_order。而对于 search-filter-company，它应该是按字母顺序排列的。 -
不要寻找“聪明”的技巧来缩短代码，尤其是当它们涉及需要不寻常的隐式类型强制的不直观操作时。更短并不意味着更清晰。您的代码应该清楚地描述您的意图。
标签： javascript jquery arrays object