【发布时间】:2012-07-22 20:58:04
【问题描述】:
我很迷茫,在下面的代码中:
while($row = mysqli_fetch_object($result)){
$similar_games[$row->game_id]['id'][] = $row->id;
$similar_games[$row->game_id]['name'][] = $row->name;
$similar_games[$row->game_id][$type] = 0;
}
foreach($similar_games as $originalGameKey => $originalGame){
//Can be a case where union gets unset, and not populated. scares ksort();
$union = array();
$similar_values = array();
$union = $similar_concepts;
foreach($originalGame['id'] as $similarGameKey => $similarGame){
if(!isset($union[$similarGame])){
$union[] = $similarGame;
}
}
foreach($originalGame['id'] as $similarGameKey => $similarGame){
if(isset($union[$similarGame])){
$similar_values[] = $similarGame;
}
}
$similar_games[$originalGameKey]["union"] = $similar_values;
}
在$similar_values[] = $similarGame; 线上,我试图获取$row->name 而不是$row->id
但我不知道如何让基于 ['id'] 的 foreach 访问 ['name'] 值。
如果这太令人困惑,我可以尝试澄清一下,但我自己在这里遇到了麻烦。
【问题讨论】:
标签: php arrays algorithm multidimensional-array