奇怪的 Javascript 字符串操作行为

Question

我不是 Javascript 专家，但我开始觉得这有点奇怪！本质上，我写了这个函数：

 function onChange()
 {
      if(this.responseText.length != 0) {

       // Get the new HTML Page requested from the servlet.
       var currentHTML = new XMLSerializer().serializeToString(document);
       var newHTML = this.responseText;

       currentHTML = currentHTML.replace('/\s+/g','');
       currentHTML = currentHTML.replace('/[\n\r]/g','');
       currentHTML = currentHTML.replace('/\t/g','');

       newHTML = newHTML.replace('/\s+/g','');
       newHTML = newHTML.replace('/[\n\r]/g','');
       newHTML = newHTML.replace('/\t/g','');


       // (There's also some alerts here just to get the output)
 }

现在，当函数获取currentHTML 和newHTML 的值时，它会将它们传递给正则表达式方法，这些方法旨在去除所有空格、回车符和制表符。然而，这并没有发生。没有错误，没有错误。通过，它丝毫没有改变变量。

Answer 1

正则表达式文字不被引号包围。你需要改变这个：

currentHTML.replace('/\s+/g','');

到这里：

currentHTML.replace(/\s+/g,'');

另外，你的替换有点多余。 \s 已经匹配制表符和换行符（以及空格！）。

Answer 2

我认为你忘记关闭 if body.

function onChange()

{ if(this.responseText.length != 0) {

   // Get the new HTML Page requested from the servlet.
   var currentHTML = new XMLSerializer().serializeToString(document);
   var newHTML = this.responseText;

   currentHTML = currentHTML.replace('/\s+/g','');
   currentHTML = currentHTML.replace('/[\n\r]/g','');
   currentHTML = currentHTML.replace('/\t/g','');

   newHTML = newHTML.replace('/\s+/g','');
   newHTML = newHTML.replace('/[\n\r]/g','');
   newHTML = newHTML.replace('/\t/g','');

   }
   // (There's also some alerts here just to get the output)

}