如何将 n-D 数组转换为 ruby 中的字符串？ [关闭]答案

【问题标题】：How to make n-D array into a string in ruby? [closed]如何将 n-D 数组转换为 ruby 中的字符串？ [关闭]
【发布时间】：2015-06-08 08:21:27
【问题描述】：

我有一个多维数组：

[
  [:C],
  [:C, [:C]],  
  [:C, [[:C]]],
  [:C, [:C, [:C]]],
  [:C, [:C, [:C, :C]]],  
  [:C, [:C, [:C, [:C]]]],
  [:C, [:C, [:C, [:C, :C]]]],
]

我需要把它翻译成这样的字符串：

"C C(C) C((C)) C(C(C)) C(C(CC)) C(C(CC)) C(C(C(C)))"

为了清楚起见，这里是内部数组，每个都显示有翻译后的字符串：

[:C]                       => "C"
[:C, [:C]]                 => "C(C)"
[:C, [[:C]]]               => "C((C))"
[:C, [:C, [:C]]]           => "C(C(C))"
[:C, [:C, [:C, :C]]]       => "C(C(CC))"
[:C, [:C, [:C, [:C]]]]     => "C(C(CC))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(C)))"

我尝试过使用 flatten 和 concatenate，但我没有得到期望的结果。我想要带括号的，这样可以很容易确定。如果我使用flatten 或concat，我会得到CCCCCCCCCCCCC。一世想要用括号括起来。

【问题讨论】：

你能解释一下你的需求逻辑吗？为什么有些 C 在输出中应该有括号并不明显。一些更简单的例子会有所帮助。
chemical=Array.new(l,[:C]) 该化学物质是 N-d 阵列。它附有一些分支。您在第二个 C 中看到数组中有一个数组。所以我想用括号来区分它。 @MaxWilliams
那里有三层嵌套，所以说“数组中有一个数组”并没有多大帮助。您能否为您的输入问题添加一些简单的示例，这些示例不会产生括号内的输出，然后是它的更改版本？假设没有人对你的化学作业或任何内容一无所知。
如果没有带有数组的数组，那么我可以简单地展平或连接。例如：[[:C, [":Br"]], [:C, [":Br"]], [:C, [":Br"]]]，输出应该是 CBrCBrCBr。但主要问题是带有数组的数组。 @MaxWilliams
嗯，整个就是一个数组，里面有3个数组，然后他们里面都有另外一个数组。所以，这里有三层嵌套数组。所以数组中有很多数组，但你说它们不应该有括号。请在您的问题中非常清楚地指定您的要求规则，因为只是说“数组中的数组”没有帮助。

标签： ruby-on-rails arrays ruby string random

【解决方案1】：

一旦您注意到第一级和其他级别的格式不同，算法就很简单了。所以为了清楚起见，我不得不使用两个不同的功能。除此之外，该算法非常不言自明。但即便如此，我还是尽可能清楚地评论它。

data = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]],
       [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]],
       [:C, [:C, [:C, [:C, :C]]]]

def format_step(e) # Expects an array, since all the elements of data are arrays.
  e.map do |x| # So for each element, get the following
    if x.is_a?(Array)
      "(#{ format_step(x) })" # ...then call the same function on it
    else
      x.to_s # convert to string and return
    end
  end.join # this way map returns an array of strings here, join them
end

def reformat(data) # This rule is only for the first level and is a bit different
  data.map do |element| # For each element of the root array
    format_step(element) # do this
  end.join(' ') # ..and join the results with spaces
end

puts reformat(data)

【讨论】：

非常感谢第二个功能确实有效。我对映射了解不多。仍然在学习。 :D
@PriyaGupta 很好，他们一起工作。两条规则，两种功能。

【解决方案2】：

假设要求是这样的：

[:C]                       => "C"
[:C, [:C]]                 => "C(C)"
[:C, [[:C]]]               => "C(C)"
[:C, [:C, [:C]]]           => "C(C(C))"
[:C, [:C, [:C, :C]]]       => "C(C(CC))"
[:C, [:C, [:C, [:C]]]]     => "C(C(C(C)))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(CC)))"

这不是您的问题所说的，但在 D-Side 的评论中，我认为这就是您想要的：基本上，用花括号替换除外部括号外的所有括号，并删除外部括号和不需要的格式。

def to_formatted_string(array)
  array.inspect.gsub(/^\[|\]$|[\:\,\s]/,"").gsub("[","(").gsub("]",")")
end

测试 = [ [：C]， [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]] ]

tests.each{|arr| puts "#{arr.inspect} => #{to_formatted_string(arr).inspect}"};false

给予

[:C] => "C"
[:C, [:C]] => "C(C)"
[:C, [[:C]]] => "C((C))"
[:C, [:C, [:C]]] => "C(C(C))"
[:C, [:C, [:C, :C]]] => "C(C(CC))"
[:C, [:C, [:C, [:C]]]] => "C(C(C(C)))"
[:C, [:C, [:C, [:C, :C]]]] => "C(C(C(CC)))"

【讨论】：

您将这些视为字符串。这不起作用。

【解决方案3】：

您可以根据需要创建字符串，如下所示：

array = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]
array.inspect.gsub(/(\[|\]|:C)/, '[' => '(', ']' => ')',':C' => 'c')

控制台输出：

2.1.2-p95 :029 > array = [:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]
 => [[:C], [:C, [:C]], [:C, [[:C]]], [:C, [:C, [:C]]], [:C, [:C, [:C, :C]]], [:C, [:C, [:C, [:C]]]], [:C, [:C, [:C, [:C, :C]]]]] 
2.1.2-p95 :030 > array.inspect.gsub(/(\[|\]|:C)/, '[' => '(', ']' => ')',':C' => 'c')
 => "((c), (c, (c)), (c, ((c))), (c, (c, (c))), (c, (c, (c, c))), (c, (c, (c, (c)))), (c, (c, (c, (c, c)))))"

【讨论】：