在字符串数组中搜索订单

Question

我想知道字符串数组中的搜索结果如何：

示例：

String[] chestOrder = new String[]{"silver", "silver", "silver", "gold", "silver", "silver", "gold", "silver", "silver",

如果我搜索： Silver Silver Silver Gold，我怎样才能得到下一个字符串？所以这里是银色的。

谢谢。

Answer 1

我的理解是，如果连续3次获得银，之后获得金，你想获得下一个字符串。

所以在这段代码中，它检查是否有连续的银银银金，并将下一个字符串获取到变量并打印出来。

    String[] chestOrder = new String[]{"silver", "silver", "silver", "gold", "silver", "silver", "gold", "silver", "silver"};
    String next = null;

    for(int i = 0 ; i < chestOrder.length ; i++){
        if(i <= (chestOrder.length - 3)){
            if(chestOrder[i].equals("silver") && chestOrder[i+1].equals("silver") && chestOrder[i+2].equals("silver") && chestOrder[i+3].equals("gold")){
            next = chestOrder[i+4];
            }
        }

    }

    System.out.println(next);

Answer 2

 public static void searchStringArray() {
        String[] chestOrder = { "silver", "silver", "silver", "gold", "silver",
                "silver", "gold", "silver", "silver" };

        String searchString = "silver silver silver gold";
        StringBuilder tempStr = new StringBuilder();
        for (String s : chestOrder) {
            tempStr.append(s + " ");
        }
        Scanner scanner = new Scanner(tempStr.toString());
        while (scanner.hasNext()) {
            if (null != scanner.findInLine(searchString)) {
                System.out.println("" + scanner.next());
            } else {
                scanner.next();
            }
        }
        scanner.close();

    }