角度应用程序的php JSON数据结构答案

【问题标题】：php JSON data structure for angular app角度应用程序的php JSON数据结构
【发布时间】：2013-10-04 02:38:25
【问题描述】：

我正在尝试将 mysql 响应格式化为对象数组，以便 Angular 可以轻松遍历数据。

mysql结果：

[{
    "FIAccountsID": "99",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "1"
},
{
    "FIAccountsID": "99",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "2"
},
{
    "FIAccountsID": "100",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "1"
},
{
    "FIAccountsID": "100",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "2"
},
{
    "FIAccountsID": "101",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "1"
},
{
    "FIAccountsID": "101",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "2"
},
{
    "FIAccountsID": "102",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "1"
},
{
    "FIAccountsID": "102",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "2"
},
{
    "FIAccountsID": "103",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "1"
},
{
    "FIAccountsID": "103",
    "AccountName": "",
    "AccountCustomName": "Brothers",
    "AccountNumber": "99-123123123",
    "AccountTypeName": "IRA",
    "FinancialInstName": "Testes",
    "FinancialInstID": "9",
    "UserID": "1",
    "ofxStatusCode": "500",
    "UserAccountID": "09128-vc-12",
    "FirstName": "Someones",
    "LastName": "Name",
    "Status": "2"
}......

这里是 PHP：

while($row = mysqli_fetch_assoc($result))   
{ 

  $uid = $row['UserID'];
  $name = $row['FirstName'].' '.$row['LastName'];
  $fiid = $row['FinancialInstID'];
  $fi = $row['FinancialInstName'];
  $acctID = $row['FIAccountsID'];


  $rows[$uid]['name'] = $name;
  $rows[$uid]['uid'] = $uid;
  $rows[$uid]['fi'][$fiid]['name'] = $fi;
  $rows[$uid]['fi'][$fiid]['acct'][$acctID]['name'] = $row['AccountCustomName'];

}

print json_encode($rows);

这是我得到的：

{
"1": {
    "name": "Some Name",
    "uid": "1",
    "fi": {
        "9": {
            "name": "Testes",
            "accts": {
                "99": {
                    "name": "name 1"
                },
                "100": {
                    "name": "name 2"
                },
                "103": {
                    "name": "name 3"
                }
            }
        }
    }
},
"2": {
    "name": "Another Name",
    "uid": "2",
    "fi": {
        "7": {
            "name": "Trevor's Brokerage House",
            "accts": {
                "1": {
                    "name": "Sally's 401k Account"
                },
                "2": {
                    "name": "retirement"
                },
                "3": {
                    "name": "Some other account"
..........

想要的结果：

[
  {
    "users": [
        {
            "name": "Some Name",
            "uid": "1",
            "fi": [
                {
                    "name": "Testes",
                    "acct": [
                        {
                            "name": "name 1"
                        },
                        {
                            "name": "name 2"
                        },
                        {
                            "name": "name 3"
                        }
                    ]
                }
            ]
        },
        {
            "name": "Another Name",
            "uid": "2",
            "fi": [
                {
                    "name": "Trevor's Brokerage House",
                    "acct": [
                        {
                            "name": "Sally's 401k Account"
                        },
                        {
                            "name": "retirement"
                        },
                        {
                            "name": "Some other account"
..........

我想知道如何在嵌套数组前面没有唯一键的数据结构

【问题讨论】：

$json = array('users'=>array(array('name'=>'name one', ...), array('name'=> 'name two'), ...));
问题是如果我这样做，结果集中的每一行都会覆盖最后一行？

标签： php mysql arrays json angularjs

【解决方案1】：

问题是，如果您定义键，json_encode 将读取它们。如果您不想要键，请声明没有它们的数组。所以，你需要做的是根据你想要的输出来构造你的数组。

但是数据的排列方式使得正确格式化它有点困难。我能看到的解决方案是做你已经在做的事情：

while($row = mysqli_fetch_assoc($result))   
{ 

  $uid = $row['UserID'];
  $name = $row['FirstName'].' '.$row['LastName'];
  $fiid = $row['FinancialInstID'];
  $fi = $row['FinancialInstName'];
  $acctID = $row['FIAccountsID'];


  $rows[$uid]['name'] = $name;
  $rows[$uid]['uid'] = $uid;
  $rows[$uid]['fi'][$fiid]['name'] = $fi;
  $rows[$uid]['fi'][$fiid]['acct'][$acctID]['name'] = $row['AccountCustomName'];

}

然后你重新访问数组并使用array_values删除所有键：

foreach ($rows as $uid => $data)
{
    foreach ($data['fi'] as $fiid => $fi)
    {
        $rows[$uid]['fi'][$fiid]['acct'] = array_values($fi['acct']);
    }
    $rows[$uid]['fi'] = array_values($rows[$uid]['fi']);
}
// Here you format the outer array:
$rows = array(array('users' => array_values($rows)));

结果如下：

[
    {
        "users": [
            {
                "name": "Someones Name",
                "uid": "1",
                "fi": [
                    {
                        "name": "Testes",
                        "acct": [
                            {
                                "name": "Brothers"
                            },
                            {
                                "name": "Brothers"
                            },
                            {
                                "name": "Brothers"
                            },
                            {
                                "name": "Brothers"
                            },
                            {
                                "name": "Brothers"
                            }
                        ]
                    }
                ]
            },
            {
                "name": "Someones Name",
                "uid": "2",
                "fi": [
                    {
                        "name": "Testes",
                        "acct": [
                            {
                                "name": "Brothers"
                            },
                            {
                                "name": "Brothers"
                            }
                        ]
                    }
                ]
            }
        ]
    }
]

【讨论】：

不允许多个用户？
“多用户”是什么意思？这样它就会有一个“users”键，它的值是一个用户数组，就像你给出的例子一样。
我已经有了带有唯一键的完整工作输出（在原始帖子中）。我想知道如何拥有没有唯一键前缀嵌套数组的数据结构
@user2762149 我编辑了答案，看看它是否是你想要的（另外，你想要的输出样本会很好，我不知道你为什么从问题中删除）。跨度>
我觉得这个问题令人困惑。我在问题中的格式是我想要的，除了我不知道嵌套数组前缀的索引是什么。你贴的代码和之前一样吗？