【发布时间】:2019-11-12 03:40:04
【问题描述】:
我正在尝试使用 AJAX 请求将我在单独文件中的 4 个 JSON 数组放入我的主文件中。出于某种原因,我似乎无法将数组转换为变量并将其显示在控制台日志中。 这是 JSON 文件的结果:
[[5,10,10.99,10.99,13,5,14.31,1,1,5,5,5,1,5,3,3,5,5,1,5,10.32,10.32,5,8,5,10,5,5,19,5,7.36,7.36,5,12.2,12.2,2.2,2.2,23.3,5,10.87,6.87,6.87,5,5,10,10,10,10,5,5,5,5,5,0,5,5],
[8,12.5,12.5,12.53,12.53,8,10.11,1,1,8,8,8,1,8,3,3,8,8,1,8,12.83,32.32,8,8,8,10,8.31,8,10,8,18.2,18.2,8,10.3,10.3,2.29,2.29,12.3,8,8.23,2.23,2.23,8,8,10,10,10,20,5,5,5,5,8,0,8,2],
[6,8.86,8.86,8.87,8.87,6,8.33,1,2,6,2,3,1,6,3,8,6,6,1,6,8.32,7.32,6,8,6,10,3.31,6,12,6,12.3,12.3,6,11.1,11.1,4.09,4.09,33.1,6,5.16,12.16,2.16,6,6,10,20,30,30,30,30,5,0,6,0,6,5],
[19,31.36,32.36,32.4,34.4,19,32.76,3,4,19,15,16,3,19,9,14,19,19,3,19,31.47,49.96,19,24,19,30,16.62,19,41,19,37.86,37.86,19,33.6,33.6,8.6,8.6,68.7,19,24.26,21.26,11.26,19,19,30,40,50,60,40,40,15,10,19,0,19,12]]
这就是我尝试将它放入我的主页的方式:
function callback(response) {
var array1 = response[0];
var array2 = response[1];
var array3 = response[2];
var array4 = response[3];
console.log(array1);
}
$.ajax({
url: 'loadchart.php',
success: callback
});
我试图只获取所有的array1 得到的结果只是一个括号:
[
来自 loadchart.php 的代码:
<?php
session_start();
if(!isset($_SESSION['usersId']))
{
header("Location: ../index.php");
exit();
}
else
{
include_once 'includes/dbh.inc.php';
}
$id = $_SESSION['userId'];
$dBname = "infosensor";
$conn = mysqli_connect($servername, $dBUsername, $dBPassword, $dBname);
$sql = "SELECT sensor1, sensor2, sensor3 FROM `$id`;";
$result = mysqli_query($conn, $sql);
$jsonsensor1 = array();
$jsonsensor2 = array();
$jsonsensor3 = array();
$jsonsensorsum = array();
if (mysqli_num_rows($result) > 0)
{
while ($row = mysqli_fetch_assoc($result))
{
$jsonsensor1[] = intval($row['sensor1'] * ($p = pow(10, 2))) / $p;
$jsonsensor2[] = intval($row['sensor2'] * ($p = pow(10, 2))) / $p;
$jsonsensor3[] = intval($row['sensor3'] * ($p = pow(10, 2))) / $p;
$jsonsensorsum[] = intval(($row['sensor1'] + $row['sensor2'] + $row['sensor3']) * ($p = pow(10, 2))) / $p;
$data = [$jsonsensor1,$jsonsensor2,$jsonsensor3,$jsonsensorsum];
}
}
echo json_encode($data);
【问题讨论】:
-
能分享
loadchart.php的代码吗? -
当然,我会快速编辑
-
@pindev 你去 :)
-
您是否检查了浏览器开发者工具的
network面板以检查API 是否返回正确的数据? -
我该怎么做?
标签: javascript arrays json ajax