【发布时间】：2019-10-11 19:29:46
【问题描述】：
我要创建一个应用程序，该应用程序至少需要 5 名员工的身份证、姓名、工资率和工作时间。然后我要将工资率和工作时间加在一起，以在初始查询结束时显示每个员工的总工资。我被困在如何将它添加到向量中请帮助！
**这是我们的老师给我们的作业**
http://itweb.fvtc.edu/ag/?u=3&f=cpp-assignment4
我添加了一个向量并添加了员工的所有基本信息
#include <iostream>
#include <conio.h>
#include <string>
#include <vector>
using namespace std;
struct Employee
{
int id;
string firstName;
string lastName;
float payRate;
int hours;
};
int main()
{
/*========= other way of adding employee information ==========*/
/*const int NUM_EMPLOYEE = 5;
Employee employee[NUM_EMPLOYEE];
for (int i = 0; i < 5; i++)
{
cout << "ID of employee " << (i + 1) << ": ";
cin >> employee[i].id;
cout << "First Name of employee " << (i + 1) << ": ";
cin >> employee[i].firstName;
cout << "Last Name of employee " << (i + 1) << ": ";
cin >> employee[i].lastName;
cout << "Pay rate for employee " << (i + 1) << ": ";
cin >> employee[i].payRate;
cout << "Hours worked " << (i + 1) << ": ";
cin >> employee[i].hours;
}*/
/*========= End of other way of adding employee information ==========*/
vector<Employee> employees;
char Another = 'y';
while (Another == 'y' || Another == 'Y')
{
Employee e;
cout << "Enter employee ID: \n";
cin >> e.id;
cout << "Enter employee first name: \n";
cin >> e.firstName;
cout << "Enter employee last name: \n";
cin >> e.lastName;
cout << "Enter employee pay rate: \n";
cin >> e.payRate;
cout << "Enter employee hours worked: \n";
cin >> e.hours;
employees.push_back(e);
cout << "Another? (y/n): \n";
cin >> Another;
}
float sum = 0;
vector<Employee>::iterator it = employees.begin();
for (; it != employees.end(); it++)
{
cout << "ID of employee: \n" << it->id << ": \n"
<< "Employees name: \n" << it->firstName << " " << it->lastName << ": \n"
<< "Employee pay rate: \n" << it->payRate << ": \n"
<< "Employee hours worked: \n" << it->hours << "\n";
}
float avg = sum / employees.size();
Employee e;
/*cout << " ID of employees: \n" << e.id;
cout << " Name of employees: \n" << e.firstName << " " <<
e.lastName;*/
cout << "Gross pay of employees: \n" << avg;
_getch();
return 0;
}
向用户显示所有员工的 ID、姓名和总工资
【问题讨论】：
-
对我来说看起来很合理。如果您不小心在需要整数的地方输入了字符串，可能会出现问题，因此我强烈建议您在使用输入的任何值之前测试流是否成功输入，
-
您是否特别关注“总工资”部分？您所要做的就是像打印员工信息一样遍历员工，然后计算
it->payRate * it->hours。然后你可以把它放在Employee的新字段中，或者打印它，或者你需要做的任何其他事情。 -
当您打印员工时，您不会对
sum做任何事情。 -
见函数
std::toupper()。像if (toupper(Answer) == 'Y')一样使用它。不需要两个比较。如果你不喜欢toupper，请查看它的兄弟tolower。 -
@0x5453 好吧，我仍然不知道如何让它工作。你刚刚给我的it-> payrate，由于我运行它时出现一些调试错误，它仍然无法正常工作。这是我更新的代码。