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Question

计算定冠词和不定冠词

这就是我现在所拥有的。我是新手，我想我必须对数组做点什么？所以我的第一个问题是如何将输入变成一个列表。

import sys
    def main():
        indefinite = 0
        definite = 0
        article = ""

        for line in sys.stdin:
            line  = line.strip()

            for word in line.split():
                if article == 'een' in line:
                    indefinite = indefinite + 1
                if article == 'het' in line:
                    definite   = definite + 1
                if article == 'de' in line: 
                    definite   = definite + 1

        print(indefinite)
        print(definite)
    main()

Answer 1

您的if 语句是错误的，因为您没有使用for 变量word，它应该是if word=='xxx':，或者更好的是您可以跳过所有if 语句并使用indefinite+=(word=='een') 和@987654326 @ 使用 True 为 1 而 False 为 0 的事实

在您的程序更“Pythonic”版本的下方（我的代码是 Python 2.7，需要稍作转换才能在 Python 3 中工作）：

import re, itertools, sys

def main():
    indefinite = 0
    definite = 0

    for line in sys.stdin:
        # regular expression to find articles in line
        # match is a list with all the articles found
        match=re.findall(r"\been|de|het\b",line,re.I)

        # list compreension to create an articles dictionary
        # itertools.groupby make an iterator that returns consecutive keys and groups from the iterable.
        articles={k: len(list(g)) for k,g in itertools.groupby(match)}

        # count definite/indefinite articles
        for k in articles.keys():
            if k in ['het','de']:
                definite+=articles[k]
            else:
                indefinite+=articles[k]

    print "%d definite articles, %d indefinite articles" % (definite, indefinite)

main()